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3 years ago

a one gram sample of hematite up more space than a one gram sample of malachite. what mineral characteristic does this refer to

1 answer:

7 0

I think the mineral characteristics that the one gram sample of hematite taking up more space than a one gram sample of malachite is DENSITY.

The density of hematite is 5.26 g/cm³
The density of malachite is 3.6 to 4 g/cm³

Other physical characteristics of minerals are Color, Streak, Luster, Hardness, Cleavage, Fracture, Tenacity, and Crystal Habit.

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Hydrogen-3 has a half-life of 12.32 years. A sample of H-3 weighing 3.02 grams is left for 15.0 years. What will the final weigh

kaheart [24]

Answer:

$\large \boxed{\text{1.38 g}}$

Explanation:

Two important formulas in radioactive decay are

$(1) \qquad t_{\frac{1}{2}} = \dfrac{\ln 2}{k}\\\\(2) \qquad \ln \left(\dfrac{N_{0}}{N}\right) = kt$

1. Calculate the decay constant k

$\begin{array}{rcl}t_{\frac{1}{2}} &=& \dfrac{\ln 2}{k}\\\\\text{12.32 yr} &= &\dfrac{\ln 2}{k}\\\\k & = & \dfrac{\ln 2}{\text{12.32 yr}}\\\\& = & \text{0.056 26 yr}^{-1}\\\end{array}$

2. Calculate the mass remaining

$\begin{array}{rcl}\ln \left(\dfrac{A_{0}}{A}\right) &= &kt \\\\\ln \left(\dfrac{\text{3.20 g}}{A}\right) &= &\text{0.056 26 yr}^{-1}\times \text{15 yr} \\\\\ln \left(\dfrac{\text{3.20 g}}{A}\right) &= &0.8439 \\\\\dfrac{\text{3.20 g}}{A} &= &e^{0.8439} \\\\\dfrac{\text{3.20 g}}{A}&= &2.325 \\\\A &= &\dfrac{\text{3.20 g}}{2.325}\\\\&= & \textbf{1.38 g}\\\end{array}\\\text{The final mass of the sample will be $\large \boxed{\textbf{1.38 g}}$}$

8 0

3 years ago

Chris noticed a high-pressure system in the weather forecast for Monday

Alchen [17]

Answer:

A. Clear and Sunny

Explanation:

The answer would be A. Clear and Sunny. A high pressure system occurs where the air mass above the Earth is denser than in surrounding areas, and therefore exerts a higher force or pressure. They usually happen with li9ght winds. Using process of elimination, it could not be D. Warm and Stormy, C. Cloudy and Rainy, or B. Cold and Stormy because all have wet climates.

5 0

2 years ago

23.495 g sample of aqueous waste leaving a fertilizer manufacturer contains ammonia. The sample is diluted with 72.311 g of wate

Otrada [13]

Answer:

1.86% NH₃

Explanation:

The reaction that takes place is:

HCl(aq) + NH₃(aq) → NH₄Cl(aq)

We calculate the moles of HCl that reacted, using the volume used and the concentration:

32.27 mL ⇒ 32.27/1000 = 0.03227 L

0.1080 M * 0.03227 L = 3.4852x10⁻³ mol HCl

The moles of HCl are equal to the moles of NH₃, so now we calculate the mass of NH₃ that was titrated, using its molecular weight:

3.4852x10⁻³ mol NH₃ * 17 g/mol = 0.0592 g NH₃

The weight percent NH₃ in the aliquot (and thus in the diluted sample) is:

0.0592 / 12.949 * 100% = 0.4575%

Now we calculate the total mass of NH₃ in the diluted sample:

Diluted sample total mass = Aqueous waste Mass + Water mass = 23.495 + 72.311 = 95.806 g

0.4575% * 95.806 g = 0.4383 g NH₃

Finally we calculate the weight percent NH₃ in the original sample of aqueous waste:

0.4383 g NH₃ / 23.495 g * 100% = 1.86% NH₃

6 0

3 years ago

Predict how heat would flow if beaker a is moved so that it is touching beaker b

Arlecino [84]

Heat flows from hot to cold, therefore heat, denoted as q would flow from beaker A into beaker B

7 0

3 years ago

The map shows watersheds with a high potential for soil, nitrogen, and pesticide runoff. If you were in charge of handling the p

Yuri [45]

Answer:

Here are some possible answers:

Why are watersheds in the Midwest more prone to pollution in than other areas in the country?

What are the current flood and pollution control measures in place in high-risk regions?

What are the flaws with the systems used to control pollution in high-risk regions?

What can the officials and scientists in one region learn from those in another region?

What would the effects on residents be if we made changes to current flood and pollution control measures?

Explanation:

When manure or commercial fertilizers enter surface water, the nutrients they release stimulate microorganism growth. The growth and reproduction of microorganisms reduce the dissolved oxygen content of the water body. Without sufficient dissolved oxygen in surface water, fish and other aquatic species suffocate.

7 0

3 years ago