Ask question

Ask question

All categories

3 years ago

5

In 2000, a total of 531,285 live births were recorded in state of California. In 2006, the total number of live births rose to 5

62,157. What is the % increase of live births for the 6-year period from 2000 to 2006, to the nearest thousands

1 answer:

zhannawk [14.2K]3 years ago

6 0

Percent increase
find increase
then divided that by original

562157+531285=30872=increase

now put that over original
30872/531285=0.05810817/1
percent means partst out of 100
make bottom number 100
0.05810817/1 times 100/100=5.810817/100=5.810817%
thousanth
5.811%

You might be interested in

Which formula gives the x-coordinates of the maximum values for y = cos(x)?

solong [7]

We have been given a function $y=\cos(x)$ . We are asked to find the formula which gives the x-coordinates of the maximum values for given function.

We know that cosine function oscillates between $-1$ and 1 that is minimum value of cosine is $-1$ and maximum value is $1$ .

We also know that $\cos(0)=1$ and after period of cosine is $2\pi$ . This means after every $2\pi$ , we will get to $1$ .

So maximum of cosine is $2\pi n$ , where n is an integer.

Therefore, our required formula is $2\pi n$ , where, $n=0,\pm 1,\pm 2,\pm3,...$

7 0

4 years ago

For the following right triangle, find the side length. Round your answer to the nearest hundredth

IRINA_888 [86]

Answer:9.75

Step-by-step explanation:12x12 =144 and 7x7= 49 subtract 144-49 and get 95 the square root of 95 is approximately 9.747 rounded to the nearest hundredths place is 9.75

4 0

3 years ago

Read 2 more answers

Simplify this equation <br> Thanks a lot!!!

den301095 [7]

Answer:

-1

Step-by-step explanation:

We need to simplify the given expression . The given expression is ,

$\rm\implies ( 2 \sqrt6 +5)^{2n-1} ( 2\sqrt6 - 5)^{2n-1}$

Here we can see that the power of the both exponent is same that is (2n+1) . Recall the property of exponents ,

$\bf\implies a^m \times b^m = (ab)^m$

Using this property , we have ,

$\rm\implies ( 2 \sqrt6 +5)^{2n-1} ( 2\sqrt6 - 5)^{2n-1}$

This can be written as ,

$\rm\implies\{( 2 \sqrt6 +5) ( 2\sqrt6 - 5)\}^{2n-1}$

Simplifying using ( a+b)(a-b) = a² - b² ,

$\rm\implies\{( 2 \sqrt6)^2 -5^2 \}^{2n-1}\\\\\rm\implies ( 24 - 25)^{2n-1}$

Subtracting the numbers inside the brackets ,

$\rm\implies (-1)^{2n - 1 }$

Now we know that every odd number is in the form of 2n -1 , where n is any integer. Therefore , the <u>power is odd</u> .

Since the base is (-1) , for even power it is 1 and for odd power it is -1 . Therefore the final answer is ,

$\rm\implies\boxed{\quad \red{ -1 }\quad }$

<u>Hence </u><u>the</u><u> </u><u>required</u><u> answer</u><u> is</u><u> </u><u>(</u><u>-</u><u>1</u><u>)</u><u> </u><u>.</u>

4 0

3 years ago

Someone please help me

allsm [11]

Answer:

Solutions: $x = \frac{-3}{ 4} + i \sqrt{39}$ , $x = \frac{-3}{4} - i \sqrt{39}$

Step-by-step explanation:

Given the quadratic equation, 2x² + 3x + 6 = 0, where a =2, b = 3, and c = 6:

Use the <u>quadratic equation</u> and substitute the values for a, b, and c to solve for the solutions:

$x = \frac{-b +/- \sqrt{b^{2} - 4ac} }{2a}$

$x = \frac{-3 +/- \sqrt{3^{2} - 4(2)(6)} }{2(2)}$

$x = \frac{-3 +/- \sqrt{9- 48} }{4}$

$x = \frac{-3 +/- \sqrt{-39} }{4}$

$x = \frac{-3 + i \sqrt{39} }{4}$ , $x = \frac{-3 - i \sqrt{39} }{4}$

Therefore, the solutions to the given quadratic equation are:

$x = -\frac{3}{ 4} + i \sqrt{39}$ , $x = -\frac{3}{4} - i \sqrt{39}$

4 0

3 years ago

The amount of time it takes a swimmer to swim a race varies inversely as the average speed of the swimmer. A swimmer finishes a

yarga [219]

Answer:

5 average speed

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers