All categories

3 years ago

Determine o valor de "m" para que o gráfico da função f(x)=3x-n-7 :

Mathematics

1 answer:

IrinaVladis [17]3 years ago

3 0

Can you translate to English please then I can help

You might be interested in

Can anyone explain to me how to find a locus of any point

joja [24]

Find the locus of a point P such that its ordinate is equal to the abscissa. Hence required equation of the locus of point P is y = 5x + 9. Hence required equation of the locus of point P is x = 2y + 3.

3 0

2 years ago

Compare 1/2 with 3/4 using ( <,>,=)

irga5000 [103]

1/2 < 3/4

1/2 is = 2/4

and 2/4 < 3/4
therefore 1/2 must be < 3/4

5 0

2 years ago

Read 2 more answers

A tire shop starts off with the same number of tires every month. In January,

7nadin3 [17]

Answer:

the answer is B

Step-by-step explanation:

4 0

2 years ago

Find the center and radius of circle and graph it <br><br> <img src="https://tex.z-dn.net/?f=%28x-4%29%5E%7B2%7D%20%2B%28%20y%20

sergeinik [125]

Answer:

centre = (4,-2)

radius = 3

Step-by-step explanation:

The centre-radius form of the circle equation is in the format

(x – h)² + (y – k)² = r²,

with the centre being at the point (h, k) and the radius being "r"

Given in the question an expression which can be write as

So, by translating we can say that

centre = (4,-2)

and

radius = 3

3 0

3 years ago

Greta is trying to determine the portion of green candies in various bags of green and yellow candies. Using the information bel

IrinaK [193]

Answer: a) $\dfrac{1}{3}$ b) $\dfrac{71}{100}$ c) $\dfrac{5}{9}$

Step-by-step explanation:

Since we have given that

There are green and yellow candies in each bag.

Bag A: Two thirds of the candies are yellow. What portion of the candies is green?

Part of yellow candies in bag A = $\dfrac{2}{3}$

Part of green candies in bag A would be

$1-\dfrac{2}{3}\\\\=\dfrac{3-2}{3}\\\\=\dfrac{1}{3}$

Bag B: 29 % of the candies are yellow. What portion of the candies is green?

Percentage of candies are yellow = 29%

Portion of candies are green is given by

$1-\dfrac{29}{100}\\\\=1-0.29\\\\=0.71\\\\=\dfrac{71}{100}$

Bag C: 4 out of every 9 candies are yellow. What portion of the candies is green?

Portion of yellow candies = $\dfrac{4}{9}$

Portion of green candies would be

$1-\dfrac{4}{9}\\\\=\dfrac{9-4}{9}\\\\=\dfrac{5}{9}$

Hence, a) $\dfrac{1}{3}$ b) $\dfrac{71}{100}$ c) $\dfrac{5}{9}$

6 0

2 years ago