When an spherical balloon volume is increasing at the rate of 
then the diameter of the balloon is increasing 
How can we find the rate of change of balloon's diameter ?
The volume of a spherical balloon is 
In form of diameter we can write as
Now we will differentiate both sides wrt to 
we get
Given in the question 
thus when we substitute the values we get
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function g has to be the transformation of function f. Therefore,
is the answer.
1)7; divide by 7 2)-3; divide by 2 3)8; divide by -4 4)54; multiply by 6 5)80; multiply by -10 6)-6; divide by -9 7)-5; divide by -12 8)-40; multiply by 20 9)-90; multiply by 10 10)20 11)615; plug in 205 for R and 3 in T. multiply by 3
Answer:
(2n + 1)[(2n + 1) � 1]
(2n + 1)(2n + 1 � 1)
(2n + 1)(2n), or 2n(2n + 1)
2n is an EVEN NUMBER, and adding 1 to an even number creates an ODD number
Therefore, 2n(2n+1)=EVEN NUMBER ODD NUMBER=EVEN NUMBER
Step-by-step explanation:
For rhombus A:
base = 7 in
area = 35 in²
Area of rhombus = b * h
⇒ 35 = 7 * h
⇒ h = 35/7
⇒ h = 5 in
Rhombus B:
height = 3*5 = 15 in
base = 7*3 = 21 in
Area = 15 * 21 = 315 in²
Area
of rhombus B is 9 times area of rhombus A. When the dimensions are
increased to 3 times the initial dimension, area became 9 times.
