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koban [17]
3 years ago
11

A bouncing ball reaches a height of 27 feet at its first peak, 18 feet at its second peak, and 12 feet at its third peak. Descri

be how a sequence can be used to determine the height of the ball when it reaches its fourth peak
Mathematics
2 answers:
Mrrafil [7]3 years ago
7 0

Answer:

There is a common ratio of 2/3 between the height of the ball at each bounce. So, the bounce heights form a geometric sequence: 27, 18, 12. Two-thirds of 12 is 8, so on the fourth bounce, the ball will reach a height of 8 feet.

Step-by-step explanation:

astraxan [27]3 years ago
5 0

Sample Response: There is a common ratio of 2/3 between the height of the ball at each bounce. So, the bounce heights form a geometric sequence: 27, 18, 12. Two-thirds of 12 is 8, so on the fourth bounce, the ball will reach a height of 8 feet.

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Step-by-step explanation:

1/3 * 3.14 * 4 * 11 = 46.05 (rounded to the tenth)

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Step-by-step explanation:

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Write an equation of the circle with center (4,5) and radius 9.
mixer [17]

Answer:

I'm going to write both of these because maybe you have a fill in the blank question. I don't know.

(x-4)^2+(y-5)^2=9^2

Simplify:

(x-4)^2+(y-5)^2=81

Step-by-step explanation:

(x-h)^2+(y-k)^2=r^2 is the equation of a circle with center (h,k) and radius r.

You are given (h,k)=(4,5) because that is the center.

You are given r=9 because it says radius 9.

Let's plug this in.

(x-4)^2+(y-5)^2=9^2

Simplify:

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I’m not great at math so I could easily be wrong, but

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To show work:

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