Ask question

Ask question

All categories

alukav5142 [94]

2 years ago

10

Point E is located at (2, −3) and point F is located at (−2, −1). Find the y value for the point that is 3 over 4 the distance f

rom point E to point F.
A. -2.5
B. -4.5
C. -3.5
D. -1.5

1 answer:

SVETLANKA909090 [29]2 years ago

6 0

Y-E = (3/4)(F -E)
Y = (3/4)F -(3/4)E +E
Y = (3F +E)/4
Y = (3(-1) +(-3))/4 = -6/4 = -3/2

the appropriate choice is D. -1.5

You might be interested in

If f(2) = 22 – 5, then what is the value of f(2) + f(5)?

jasenka [17]

Answer:

67

Step-by-step explanation:

With the information of f(2) = 22-5, you can assume the equation will be f(x) = 11x-5. Using this, you can calculate f(5) by doing 11(5)-5, which is 50. 22-5 is 17, so 50+17=67

5 0

2 years ago

Read 2 more answers

Use the figure and flowchart Proof to answer the question which property of equality accurately completes reason C

blagie [28]

Answer:

Step-by-step explanation:

The mesa people of the Southwest adapted their homes to their arid ... dry and barren. In order ... To adapt to their environment, the Indians of the Great Basin lived in ... American Indians of the Plateau found it relatively easy to get food because ... The Southeast cultural region was good for farming because its climate has.

7 0

3 years ago

Read 2 more answers

Please help!!!i need help

Colt1911 [192]

The answer to this question is d

4 0

3 years ago

Read 2 more answers

What is the difference? StartFraction 2 x + 5 Over x squared minus 3 x EndFraction minus StartFraction 3 x + 5 Over x cubed minu

inn [45]

Answer:

$\frac{(x+5)(x+2)}{x(x-3)(x+3)}$

Step-by-step explanation:

The given expression is

$\frac{2x+5}{x^{2} -3x} -\frac{3x+5}{x^{3} -9x} -\frac{x+1}{x^{2}-9}$

First, we need to factor each denominator

$\frac{2x+5}{x(x-3)} -\frac{3x+5}{x(x+3)(x-3)} -\frac{x+1}{(x-3)(x+3)}$

So, the least common factor (LCF) is $x(x-3)(x+3)$ , because they are the factors that repeats.

Now, we diviide the LCF by each denominator, to then multiply it by each numerator.

$\frac{(x+3)(2x+5)-3x-5-x(x+1)}{x(x-3)(x+3)} =\frac{2x^{2}+5x+6x+15-3x-5-x^{2}-x }{x(x-3)(x+3)}\\\frac{x^{2}+7x+10}{x(x-3)(x+3)}$

Then, we factor the numerator, to do so, we need to find two numbers which product is 10 and which sum is 7.

$\frac{(x+5)(x+2)}{x(x-3)(x+3)}$

Therefore, the expression is equivalent to

$\frac{(x+5)(x+2)}{x(x-3)(x+3)}$

8 0

2 years ago

Read 2 more answers

determine whether the given ordered pair is a solution to the system of equations. 6x-2y=24 -3x+3y=24 and (10,18) yes, it is a s

Anika [276]

Answer:

I love algebra anyways

the ans is in the picture with the steps

(hope it helps can i plz have brainlist :D hehe)

Step-by-step explanation:

7 0

2 years ago