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alukav5142 [94]
3 years ago
10

Point E is located at (2, −3) and point F is located at (−2, −1). Find the y value for the point that is 3 over 4 the distance f

rom point E to point F.
A. -2.5
B. -4.5
C. -3.5
D. -1.5
Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
6 0
Y-E = (3/4)(F -E)
Y = (3/4)F -(3/4)E +E
Y = (3F +E)/4
Y = (3(-1) +(-3))/4 = -6/4 = -3/2

the appropriate choice is D. -1.5
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3 years ago
Help me please please
Serggg [28]

Answer:

-2,10

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Hey Guys!
zaharov [31]
<h3>Answer: D)  -3</h3>

Explanation:

Recall that y = f(x) since both are outputs of a function.

If k = 2, then f(x) = 2 leads to y = 2 being a horizontal line drawn through 2 on the y axis. This horizontal line only crosses the cubic curve at one spot. The same can be said if k = 0 and k = -2. So we can rule out choices A,B,C.

On the other hand, if k = -3, then f(x) = -3 has three different solutions. This is because the horizontal line through -3 on the y axis crosses the cubic at 3 different intersection points.

7 0
2 years ago
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lidiya [134]

Answer:

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Formula used :

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