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Vesnalui [34]
2 years ago
6

Given AB = BC finding X= AB= BC= AC=

Mathematics
1 answer:
Archy [21]2 years ago
6 0
AC=84

2x-8
2(25)-8
50-8
42

X+17
25+17
42

42+42=84
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I am really confused about this question for math.. any help would be really appreciated:
Elina [12.6K]

y= (\frac 1 4 )^x

A reflection about the x axis, about y=0, is the mapping (x',y')=(x,-y) so

y'= -y = - (\frac 1 4)^{x'}

A dilation of 2 is the mapping (x'',y'')=(2x', 2y')

So

x'=x''/2, y'=y''/2

y''/2= - (\frac 1 4)^{x''/2}

y'' =  - 2((\frac 1 4)^{1/2})^{x''}

y''= - 2(\frac 1 2)^{x''}

We can rewrite that without the primes and combine the powers of 2.

y =  - 2^{1-x}

Let's graph these and see if we're close,

Plot y= (1/4)^x, y= - (1/4)^{x}, y = - 2^{1-x}

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Help. I need to factor and solve using the quadratic formula <br>-x^2+2x=7​
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