Answer:
A) 2.58 pounds
Step-by-step explanation:
To solve you would have to subtract the pounds of tomatoes from the pounds of lettuce. The equation would look like this,
4.36 - 1.78 = 2.58
Hope that helps and have a great day!
Answer:
90
Step-by-step explanation:
so after we cut the nessecary we get 90%
Hope this helps you
Mark as the brainlist
thank you
Answer:
D) 1/4
Step-by-step explanation:
To solve this, first lets figure out what this variable is. We know we must multiply by t. Well, looking at it, we know that t is one. So lets plug that in.
2*1/2^3(1)
Now we need to figure out what the exponent is that 2 will be raised to. To find that, find out what 3 times one is.
2*1/2^3
Now we need to solve the exponent.
2*1/8
Remember, 2 cubed is eight.
Now we need to find out what 2*1/8 is. To solve this more easily, I am going to turn two into a fraction. This will give us 2/1*1/8. Now we cross multiply, multiplying the numerators by the numerators, and the denominators by the denominators. Remember, the numerator is the top number, and the denominator is the bottom number.
If we do that, we get:
2/8
If we simplify it, we get 1/4. So the asnwer is D) 1/4
Answer:
As the calculated value of z does not lie in the critical region the null hypothesis is accepted that the GPA mean of the night students is the same as the GPA mean of the day students.
Step-by-step explanation:
Here n= 20
Sample mean GPA = x`= 2.84
Standard mean GPA = u= 2.55
Standard deviation = s= 0.45.
Level of Significance.= ∝ = 0.01
The hypothesis are formulated as
H0: u1=u2 i.e the GPA of night students is same as the mean GPA of day students
against the claim
Ha: u1≠u2
i.e the GPA of night students is different from the mea GPA of day students
For two tailed test the critical value is z ≥ z∝/2= ± 2.58
The test statistic
Z= x`-u/s/√n
z= 2.84-2.55/0.45/√20
z= 0.1441
As the calculated value of z does not lie in the critical region the null hypothesis is accepted that the GPA mean of the night students is the same as the GPA mean of the day students.
