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Leni [432]
3 years ago
15

Three balls are packaged in a cylindrical container as shown below. The balls just touch the top, bottom, and sides of the cylin

der. The diameter of each ball is 13 cm.
a. What is the volume of the cylinder? Explain your method for finding the volume.
b. What is the total volume of the three balls? Explain your method for finding the total volume.
c. What percent of the volume of the container is occupied by the three balls? Explain how you would find the percent.

Mathematics
2 answers:
never [62]3 years ago
8 0
A. The volume of the cylinder can be computed because the statement "<span>The balls just touch the top, bottom, and sides of the cylinder" gives a clue of the height and radius of the cylinder. The height is equal to 3 times the diameter of the balls, and its radius is the same as the balls' radius.

Vcylinder = </span>πr^2h = π(13/2)^2 (3*13) = 5176.56 cm^3

B. The volume of the three balls is computed using the equation of V for spheres:

Vball = 3*4*π*r^2/3 = 3451.05 cm^3

C. The answer is the equal to the total volume of the balls divided by the volume of the cylinder

3451.05(100%)/5176.56 = 66.67%
lianna [129]3 years ago
4 0
We know the following:
Cylinder volume: V₁ = π r² h
Ball (sphere) volume:V₂ = \frac{4}{3} π r³
where:
V - volume
r - radius of base of cylinder and diameter of ball
h - height of cylinder.

R = 13 cm ⇒ r = 13 ÷ 2 = 6.5
π = 3.14

a) Since balls touch all sides of cylinder (as shown in image), it can be concluded that height of cylinder is equal to sum of diameters of 3 balls and that radius of base of cylinder is equal to radius of ball:
h = 3 × r = 3 × 13 cm = 39 cm
r = 6.5 cm
So,
V₁ = <span>π r² h
</span><span>V₁ = </span>3.14 × (6.5 cm)² × 39 cm
V₁ = 5,173.9 cm³

b. The total volume of three balls is the sum of volumes of each ball:
Vₐ = 3 × <span>V₂ 
</span>Vₐ = 3 × <span>\frac{4}{3} π r³
</span>Vₐ = 3 × \frac{4}{3} 3.14<span> (6.5 cm)³</span>
Vₐ = 3,449.3 cm³

c. Percentage of the volume of the container occupied by three balls ould be expressed as ratio of volume of three balls and volume of cylinder:
V = \frac{ V_{1}}{ V_{a} } ×100 
V = \frac{3,449.3}{5,173.9} ×100
V = 0.6666 ×100
V = 66.66%
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y = 23x - 6

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Mikaela friends brought a big box of crackers to the movies. 53 crackers are whole wheat and 29 are cheese flavored. The remaini
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Answer: 123 crackers

Step-by-step explanation:

If 1/3 of the box contains sesame seed crackers, then, 2/3 of the box contains whole wheat and cheese flavored crackers.

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Let x be the total number of crackers in the box, so we will have the equation

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8 0
3 years ago
A container manufacturer plans to make rectangular boxes whose bottom and top measure x by 4x. The container must contain 12ft^3
zheka24 [161]

The height of the container should be equal to 2.57 cm, so as to minimize cost.

<h3>How to calculate the height?</h3>

First of all, we would determine the volume of the rectangular container by using this formula:

Volume = l × w × h

Where:

  • l represents the length.
  • w represents the width.
  • h represents the height.

Substituting the given parameters into the formula, we have;

Volume = x × 4x × h

Volume = 4x²h

At a volume of 12 ft³, we have:

12 = 4x²h

h = 12/4x²

h = 3/x²

For the total area of top and bottom, we have:

Area = (x × 4x) + (x × 4x)

Area = 4x² + 4x²

Area = 8x² sq. units.

Thus, the cost of top and bottom is given by:

Cost = 8x² × 1.50

Cost = $12x²

For the total area of all four sides, we have:

Area = (x × h) + (x × h) + (4x × h) + (4x × h)

Area = xh + xh + 4xh + 4xh

Area = 10xh sq. units.

Thus, the cost of all four sides is given by:

Cost = 10xh × 4.50

Cost = $45xh.

Also, the cost function would be given by:

C(x) = 12x² + 10xh

C(x) = 12x² + 10x(3/x²)

C(x) = 12x² + 30/x

Taking the first derivative, we have:

dC/dx = 24x - 30/x²

24x = 30/x²

24x³ = 30

x³ = 30/24

x = 1.08

Therefore, the height will be:

h = 3/x²

h = 3/1.08²

h = 3/1.1664

Height, h = 2.57 cm.

Read more on minimum height here: brainly.com/question/27308167

#SPJ1

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2 years ago
Use the triangles Name one pair of congruent angles.
Likurg_2 [28]
Your correct answer is option B
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