Answer:
Angle = Ф = (0) = 0
Hence, it is proved that angle between position vector r and acceleration vector a = 0 and is it never changes.
Step-by-step explanation:
Given vector r(t) =
As we know that,
velocity vector = v =
Implies that
velocity vector =
As acceleration is velocity over time so:
acceleration vector = a =
Implies that
vector a =
vector a =
Now scalar product of position vector r and acceleration vector a:
r. a =
r.a =
r.a = 0
Now, for angle between position vector r and acceleration vector a is given by:
cosФ = =
Ф = (0) = 0
Hence, it is proved that angle between position vector r and acceleration vector a = 0 and is it never changes.
I have the answer it's
X equals -4
Y equals 7
Answer:
Step-by-step explanation:
Area of square= l×l
Area of square= 6mm × 6mn
Area if square = 36 mm²
Area of triangle 1= ½b ×h
Area of triangle 1= ½ (6mm)(8mm)
Area of triangle 1 = 24 mm²
Area of triangle 2 is the same as area of traingle 1 because they have the same base and hight
: . area of triangles is 48mm²
Area of the figure= Area of square + Area of triangles
A of figure = 36+48
A of figure = 84 mm²
Option 2
Use trapezium formula
Area of trapezium= (a+b)/2 * h
a=6 mm (base)
b=8+6=14 mm (Base)
h= 6mm (height)
Therefore the area of triangle= 24mm² as calculated in option 1
Area of the figure= Area of trapezium +Area of triangle
Area of figure = 60+24
= 84 mm²