A store owner is stocking shelves.he places 37 eight-ounce packages of cheese on a shelf then he puts 24 ounce cheese on the sam
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Answer:
The question is lacking the image of the histogram, but the file attachment to this answer contains the complete question and histogram image.
The percentage of the rats that navigated the maze in less than 5.5 minutes is 84%
Step-by-step explanation:
First of all let us compute the total frequency which represents the total number of rats in the experiment.
from the information given in the question, we are told that the total number of rats involved in the experiment are 25 rats and this makes up the total frequency.
To calculate the percentage of rats that navigated the maze in less than 5.5 minutes, you will first of all need to identify the 5.5 minute point on the histogram and add all the frequencies below that point. This gives the total number of rat that navigated in less than 5.5 minutes. These frequencies from 0 to <5.5 are; 3, 8, 6, and 4. And the total is given as the sum of these frequencies shown below:
Total number of rats that navigated in less than 5.5 minutes = 3 + 8 + 6 + 4 = 21. Hence, a total of 21 rats navigated the maze in less than 5.5 minutes.
Now to find the percentage of the number of rats that navigated in less than 5.5 minutes, we have to find out what percentage of 25 (total number of rats) is 21 (number of rats that navigated in less than 5.5 minutes). This is calculated thus:
× 100 = 0.84 × 100 = 84 %.
Therefore 84% of the total number of rats navigated the maze in less than 5.5 minutes in the experiment.
