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FrozenT [24]
3 years ago
11

Solve for x x^2 b+t=x^2 e

Mathematics
2 answers:
Naily [24]3 years ago
6 0

x^2b + t = x^2e

x^2e - x^2b = t

x^2(e - b) = t

x^2 = t /(e -b)

x = √[t /(e -b)] or x = - √[t /(e -b)]

garik1379 [7]3 years ago
4 0

Answer:

x = \sqrt{\frac{t}{(e - b)} }, x = - \sqrt{\frac{t}{(e - b} }

Step-by-step explanation:

x^{2} b + t = x^{2} e

To solve this equation for x, arrange the like terms together by placing the two terms with variable x^{2} at one side of the equation and the remaining terms at the other side of the equation:

x^{2} e - x^{2} b = t

Now take the common terms out and write it as:

x^{2} (e - b) = t

x^{2} = \frac{t}{e - b}

Now take square root on both sides:

\sqrt{x^{2}} = \sqrt{\frac{t}{e - b}}

x = \sqrt{\frac{t}{(e - b)}} , x = - \sqrt{\frac{t}{(e- b)}}

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