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FrozenT [24]
3 years ago
11

Solve for x x^2 b+t=x^2 e

Mathematics
2 answers:
Naily [24]3 years ago
6 0

x^2b + t = x^2e

x^2e - x^2b = t

x^2(e - b) = t

x^2 = t /(e -b)

x = √[t /(e -b)] or x = - √[t /(e -b)]

garik1379 [7]3 years ago
4 0

Answer:

x = \sqrt{\frac{t}{(e - b)} }, x = - \sqrt{\frac{t}{(e - b} }

Step-by-step explanation:

x^{2} b + t = x^{2} e

To solve this equation for x, arrange the like terms together by placing the two terms with variable x^{2} at one side of the equation and the remaining terms at the other side of the equation:

x^{2} e - x^{2} b = t

Now take the common terms out and write it as:

x^{2} (e - b) = t

x^{2} = \frac{t}{e - b}

Now take square root on both sides:

\sqrt{x^{2}} = \sqrt{\frac{t}{e - b}}

x = \sqrt{\frac{t}{(e - b)}} , x = - \sqrt{\frac{t}{(e- b)}}

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chubhunter [2.5K]

Answer:

21

Step-by-step explanation:

0 + 1 = 1

1 + 2 = 3

3 + 3 = 6

6 + 4 = 10

10 + 5 = 15

15 + 6 = 21

Each number is added to an increase of 1 - first add 1, then add 2, then add 3,etc

Not listed but next would be 21 + 7 = 28  

so it would be 0, 1, 3, 6, 10, 15, 21, 28

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Solve the system below using substitution write your final answer as a coordinate point
Mademuasel [1]

(3, -2)

Step-by-step explanation:

y = -2x + 4

-x + 3y = -9

-x + 3 (-2x + 4) = -9

-x + -6x + 12 = -9

-7x = - 9 – 12

-7x = - 21

X = 3

We substitute x with 3 to evaluate y;

-3 + 3y = -9

3y = -6

y = -2

Elimination Method;

y = -2x + 4

-x + 3y = -9

We arrange the equations for substitution;

2x + y = 4

-x + 3y = -9

We multiply the first equation with 3 so we can substract one variable to zero;

3 (2x + y = 4)

= 6x + 3y = 12

Then we subtract the two;

6x + 3y = 12

-x + 3y = -9

7x = 21

x = 3

We evaluate y by substitution x with 3 in one of the equation;

-x + 3y = -9

-3 + 3y = -9

3y = -6

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The final answer expressed as a coordinate point is;

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7 0
3 years ago
Find the domain over which the function y = x + 6x is monotonic increasing.
iragen [17]

Answer:

x > -3

\sf (-3, \infty)

Step-by-step explanation:

Domain: input values (x-values)

Monotonic increasing:  always increasing.  
A function is increasing when its graph rises from left to right.

The graph of a quadratic function is a parabola.  If the leading term is positive, the parabola opens upwards.  The domain over which the function is increasing for a parabola that opens upwards is values greater than the x-value of the vertex.

<u>Vertex</u>

Standard form of quadratic equation:  \sf y=ax^2+bx+c

\textsf{x-value of vertex}=\sf -\dfrac{b}{2a}

Given function:

\sf y=x^2+6x

Therefore, x-value of function's vertex:

\sf \implies x= -\dfrac{6}{2}=-3

<u>Final Solution</u>

The function is increasing when x > -3

\sf (-3, \infty)

4 0
2 years ago
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