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FrozenT [24]
3 years ago
11

Solve for x x^2 b+t=x^2 e

Mathematics
2 answers:
Naily [24]3 years ago
6 0

x^2b + t = x^2e

x^2e - x^2b = t

x^2(e - b) = t

x^2 = t /(e -b)

x = √[t /(e -b)] or x = - √[t /(e -b)]

garik1379 [7]3 years ago
4 0

Answer:

x = \sqrt{\frac{t}{(e - b)} }, x = - \sqrt{\frac{t}{(e - b} }

Step-by-step explanation:

x^{2} b + t = x^{2} e

To solve this equation for x, arrange the like terms together by placing the two terms with variable x^{2} at one side of the equation and the remaining terms at the other side of the equation:

x^{2} e - x^{2} b = t

Now take the common terms out and write it as:

x^{2} (e - b) = t

x^{2} = \frac{t}{e - b}

Now take square root on both sides:

\sqrt{x^{2}} = \sqrt{\frac{t}{e - b}}

x = \sqrt{\frac{t}{(e - b)}} , x = - \sqrt{\frac{t}{(e- b)}}

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x = length of AB

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So,

(AB+DC)/2 = MN

(x+11.5)/2 = 18.7

x+11.5 = 2*18.7

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7 0
3 years ago
X= -1/5; f(x) = (25/2)x + (-91/2) =
Diano4ka-milaya [45]

Answer:

Write the problem as a mathematical expression.

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Replace the variable x with x=−1/5 in the expression.

f(−1/5)=(25/2)(−1/5)−91/2

Simplify the result.

−48

Step-by-step explanation:

4 0
3 years ago
What is the equation of the line? y=3/4x−1 y=4/3x+1 y=4/3x−1 y=3/4x+1
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Answer:

y=4/3+1

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4 0
3 years ago
A particle moves along line segments from the origin to the points (2, 0, 0), (2, 3, 1), (0, 3, 1), and back to the origin under
sweet [91]

Answer: Work done by the particle is 78 N.

Step-by-step explanation:

If C is the path the particle follows, then work done is \int_{C}^{}F.dx.

According to the question the force F=z^{2}i+5xyj+4y^2k and all four points are in the plane z=\frac{1}{4}y.

therefore, if S is the at surface with boundary C, so that S is the portion of the plane z=\frac{1}{4}y over the rectangle D=[0,2]\times [0,4].

Now,

curlF=\begin{vmatrix}i &j  &k \\  \frac{\partial }{\partial x}&\frac{\partial }{\partial y}  &\frac{\partial }{\partial z} \\  z^{2}&5xy  &4y^{2} \end{vmatrix}=8yi+2zj+5yk

By the Stoke's theorem:

\int_{C}^{}F.dx=\iint_{s}^{}curlF.dS\\\\=\iint_{D}^{}[-8y(0)-2z\left ( \frac{1}{4} \right )+5y]dA\\\\=\iint_{D}^{}\left ( -\frac{1}{2}z+5y \right )dA

=\iint_{D}^{}\left ( \frac{39}{8}y \right )dA\, \, \, \, \, \, \, \, \, Since\, \, z=\frac{1}{4}y\\\\=\int_{0}^{2}\int_{0}^{4}\frac{39}{8}y\, \, \, dy\, dx\\\\

\int_{0}^{2}\left [ \frac{39}{16}y^2 \right ]_{0}^{4}dx\\\\=\int_{0}^{2}39\, \,  dx\\\\=39\times 2\\\\=78 \, N

8 0
4 years ago
What's 0/0? <br>(Filler)<br>(Filler)<br>(Filler)
Helga [31]
This an undefined equation however it can be seen as 

0/0=1
OR
0/0=0
4 0
4 years ago
Read 2 more answers
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