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Ulleksa [173]
3 years ago
14

If its 10/16 what is answer as a decimal

Mathematics
2 answers:
Softa [21]3 years ago
4 0

\text{Hey there!}

\frac{10}{16}=10\div16= 0.625

\boxed{\boxed{\text{Answer: 0.625}}}\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\frak{LoveYourselfFirst:)}

Vedmedyk [2.9K]3 years ago
3 0

Answer:

0.625 is a decimal and 62.5/100 or 62.5% is the percentage for 10/16.

Step-by-step explanation:

Please mark brainliest and have a great day!

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A number is 6 times another number and their difference is 30. What are the numbers? ​
Alenkasestr [34]

Answer:

x=36

y=6

Step-by-step explanation:

Let the numbers be x and y

Condition 1

x=6y ----------(1)

Condition 2

x-y=30 ------------(2)

Putting 1 in 2

6y-y=30

5y=30

Dividing both sides by 5

y=6

Now

Putting y=6 in 1

We get

x=6(6)

x=36

8 0
4 years ago
A slice is made perpendicular to the base of a right rectangular prism, as shown in the figure.
worty [1.4K]
It is another rectangle
3 0
3 years ago
Find the median and mean of the data set below:<br> 13, 6, 47,0
Readme [11.4K]

Answer:

Mean=16.5

Median=9.5

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Will Mark The Brainiest that is extra points aka FULL POINTS
valentina_108 [34]
Hello!

We can solve this by using substitution

we can plug y = x - 1 into the other equation

So 2x - 3( x - 1) = -1

We can distribute the -3 to (x - 1)

2x - 3x + 3 = -1

Combine like terms

-x + 3 = -1

Subtract 3 from both sides

-x = -4

Since x is negative we can multiply both sides by -1

x = 4

We can plug x into the first equation

y = (4) - 1

y = 3

The answers are x = 4 and y = 3

Hope this helps!
6 0
3 years ago
Read 2 more answers
Find two rational expressions a / b and c / d that produce the result x − 1 / x2 when using the following operations. Answers
Mars2501 [29]

Answer:

a) Let \frac{a}{b}=\frac{-1}{x^2}, \text{ and } \frac{c}{d}=\frac{1}{x}.

Observe that

\frac{a}{b}+\frac{c}{d}=\frac{-1}{x^2}+\frac{1}{x}=\frac{-x+x^2}{x^3}=\frac{x(x-1)}{xx^2}=\frac{x-1}{x^2}

b)

Let \frac{a}{b}=\frac{1}{x}, \text{ and } \frac{c}{d}=\frac{1}{x^2}.

Observe that

\frac{a}{b}-\frac{c}{d}=\frac{1}{x}-\frac{1}{x^2}=\frac{x^2-x}{x^3}=\frac{x(x-1)}{xx^2}=\frac{x-1}{x^2}

c)

Let \frac{a}{b}=\frac{x-1}{x}, \text{ and } \frac{c}{d}=\frac{1}{x}.

Observe that

\frac{a}{b}*\frac{c}{d}=\frac{x-1}{x}*\frac{1}{x}=\frac{(x-1)1}{x*x}=\frac{x-1}{x^2}

d)

Let \frac{a}{b}=\frac{x-1}{x}, \text{ and } \frac{c}{d}=\frac{x}{1}.

Observe that

\frac{a}{b}\div\frac{c}{d}=\frac{x-1}{x}\div\frac{x}{1}=\frac{x-1}{x}*\frac{1}{x}=\frac{x-1}{x^2}

3 0
3 years ago
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