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Kaylis [27]
4 years ago
8

What is the answer to 14x - 3= 10x + 1

Mathematics
1 answer:
slava [35]4 years ago
4 0

Answer:

14x - 3 = 10x + 1

4x = 4

x = 1

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Show the work please
Neporo4naja [7]
False, False, True
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The first is false since the square root of 19 is 4 and 4/7 is not a whole number

The second is false since the square root of 40 is 6.32 which is less than 7

The last is true because the square root of 30 is 5.48 and that makes the fraction equal 3.65 which again is a whole number while 2/3 is not
3 0
3 years ago
The commutative property only works under what two operations?
lara [203]
The commutative property only works under addition and multiplication properties.
5 0
3 years ago
Two angles in a triangle measure 102 degrees and 67 degrees. What is the measure of the third angle?
Nat2105 [25]

Answer:

11 degrees

Step-by-step explanation:

The sum of the interior angles of a triangle is 180 degrees.

From 180 degrees we subtract the sum of 102 degrees and 67 degrees, obtaining 11 degrees (first answer choice)

3 0
3 years ago
Please need help on this
Rufina [12.5K]

Answer:

The first one is not a function

The second is a function

Third not a function

Fourth is a function

Step-by-step explanation:

6 0
3 years ago
Multiply the following rational expressions and simplify the result
GarryVolchara [31]

Answer:

Step-by-step explanation:

We have to solve the given expression,

\frac{9y-33y^2-3y^4}{100-49y^2}.\frac{7y^2+17y+10}{14y^2+28y}

\frac{9y-33y^2-3y^4}{100-49y^2}.\frac{7y^2+17y+10}{14y^2+28y} = \frac{-y(-9+33y+3y^3)}{100-49y^2}.\frac{7y^2+17y+10}{14y(y+2)}

                                   = \frac{-y(-9+33y+3y^3)}{(10-7y)(10+7y)}.\frac{7y^2+10y+7y+10}{14y(y+2)}

                                   = \frac{-y(-9+33y+3y^3)}{(10-7y)(10+7y)}.\frac{y(7y+10)+1(7y+10)}{14y(y+2)}

                                   = \frac{-y(-9+33y+3y^3)}{(10-7y)(10+7y)}.\frac{(y+1)(7y+10)}{14y(y+2)}

                                   = \frac{-3y(-3+11y+y^3)}{(10-7y)}.\frac{(y+1)}{14y(y+2)}

                                   = \frac{-3(-3+11y+y^3)}{(10-7y)}.\frac{(y+1)}{14(y+2)}

                                   = \frac{3(3-11y-y^3)(y+1)}{(10-7y)(14(y+2)}

3 0
3 years ago
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