Answer:
a)
Step-by-step explanation:
Previous concepts
A chi-square goodness of fit test "determines if a sample data matches a population".
A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".
Solution to the problem
Let's define some notation:
N= Total number of individuals for a population
n = Total of individuals selected from a sample
n1= number of objects/individuals with characteristic 1
n2= number of objects/individuals with characteristic 2
k1= number of levels for the variable or factor 1
k2= number of levels for the variable or factor 2
Part a
For a chi square goodness of fit test the degrees of freedom are given by:
Where k represent the total number of categories on the godness of fit test.
Part b
For a chi square test of independence the degrees of freedom are given by:
Where k1= number of levels for the variable or factor 1, k2= number of levels for the variable or factor 2 for the chi square test for independence.
EDIT - OMG IM SO SORRY, I DIDN'T REALISE THIS WAS THE WRONG QUESTION UNTIL AFTER I ANSWERED. IM SORRY
