Answer:
Step-by-step explanation:
Assuming a perpendicular line(apotherm) is extended from the midpoint of the polygon to the midpoint of one of its sides, then we can determine the length of the apotherm by applying Pythagorean theorem which is expressed as
Hypotenuse² = opposite side² + adjacent side²
Let a represent the apotherm
Hypotenuse = 4
Apotherm = a
Opposite = a(apotherm = length of each side/2)
Therefore,
4² = a² + a²
16 = 2a²
a² = 16/2 = 8
a = √8 = 2√2
The formula for determining the area of a polygon is expressed as
Area = a² × n × tan 180/n
Where n represents the number of sides of the polygon.
n = 6
Therefore,
Area = (2√2)² × 6 × tan(180/6)
Area = 48 × tan 30
Area = 27.2
Answer:
B.-4
Step-by-step explanation:
Hope it help!!!!!!
ANSWER

EXPLANATION
We determine the slope of each line using the slope formula;

The slope of BC is


The slope of AB is


The two lines are perpendicular so the product of their slopes is -1.

This implies that,




.
we are given

standard form:
We will complete x , y and z square
make all x , y and z terms together






surface:
It is an infinite paraboloid
graph:
Answer:
9* 3 ^ (x-2)
Step-by-step explanation:
g(x) = 3^x
We know a^ (b) * a^(c) = a^ (b+c)
9* 3 ^ (x+2) = 3^2 * 3 ^(x+2) = 3^(2+x+2) = 3^x+4 not equal to 3^x
3*(9^(x+2)) = 3*3^2(x+2) = 3^1 * 3^(2x+4) =3^(2x+4+1) = 3^(2x+5) not equal
9* 3 ^ (x-2) = 3^2 * 3 ^(x-2) = 3^(2+x-2) = 3^x equal to 3^x
3*(9^(x-2)) = 3*3^2(x-2) = 3^1 * 3^(2x-4) =3^(2x-4+1) = 3^(2x-3) not equal