Pls answer all 3 questions

Please answer fast

Rudik [331]

Answer:

5 a^3 c

Step-by-step explanation:

5 • a • a • c • a

There are 3 a's so it becomes a^3

5 a^3 c

7 0

3 years ago

What is the difference? 5/3-1/2 A. 4 B. 7 C. 7/6 D. 7/0 = undefined

Fofino [41]

The answer is: [C]:  " ⁷/₆ " .
____________________________________
Note:
____________________________________
(5/3) - (1/2) = ? ;
____________________________________
The LCD (lowest common denominator) of "2 and 3" is "6" ;

So we need to rewrite EACH fraction in the problem as a fraction with "6" in the denominator ;
____________________________
(5/3) = (?/6) ? ; (6÷3=2) ; (5/3) = (5*2)/(3*2) = 10/6 ;
____________________________
(1/2) = (?/6) ? ; (6÷2=3) ; (1/2) = (1*3)/(2*3) = 3/6 ;
____________________________
Rewrite the problem: "   (5/3) - (1/2) " ; as:
____________________________
10/6 - 3/6 ;
____________________________________________
  10/6 - 3/6 = (10 - 3) / 6 = (7/6) = 1 ⅙ .
____________________________________________
The answer is: " ⁷/₆ " ; or, write as: " 1 ⅙ " ; which corresponds to:
______________________________________________________
Answer choice: [C]: " ⁷/₆ " .
____________________________________________

5 0

2 years ago

Claudia spends $2.15 a day for lunch. Her cafeteria lunch account has a balance of $48.00. Which equation can be used to determi

andreev551 [17]

Answer:

d≤48/2.15

Step-by-step explanation:

Step one:

Given data

Claudia spends $2.15 a day for lunch.

We are told that her balance is $48.00

let the number of days be d

Step two:

The maximum number of days she can eat is given as

d≤48/2.15

d≤22.33 days

7 0

2 years ago

Working together, it takes two different sized hoses 20 minutes to fill a small swimming pool. If it takes 30 minutes for the la

Anuta_ua [19.1K]

Answer:

60 minutes for the larger hose to fill the swimming pool by itself

Step-by-step explanation:

It is given that,

Working together, it takes two different sized hoses 20 minutes to fill a small swimming pool.

takes 30 minutes for the larger hose to fill the swimming pool by itself

Let x be the efficiency to fill the swimming pool by larger hose

and y be the efficiency to fill the swimming pool by larger hose

To find LCM of 20 and 30

LCM (20, 30) = 60

To find the efficiency

Let x be the efficiency to fill the swimming pool by larger hose

and y be the efficiency to fill the swimming pool by larger hose

x = 60/30 =2

x + y = 60 /20 = 3

Therefore efficiency of y = (x + y) - x =3 - 2 = 1

so, time taken to fill the swimming pool by small hose = 60/1 = 60 minutes

8 0

3 years ago

What is the answer to this please help!

Butoxors [25]

$z+(-0.72)=-2.5\\\\\text{Step 1}:\ x+(-0.72)+(-0.72)=-2.5+(-0.72)\qquad\text{ERROR}\\\\CORRECT\ IS:\ x+(-0.72)-(-0.72)=-2.5-(-0.72)\\\\\text{Step 2}:\ x=-2.5+0.72\\\\\text{Step 3}:\ x=-1.78$

Subtract, not add, -0.72 from both sides.

6 0

2 years ago