3 years ago

Calculate the area of a circle with the radius of 5cm (1dp)

Mathematics

1 answer:

quester [9]3 years ago

7 0

Answer:

25π ≈ 78.5 cm squared

Step-by-step explanation:

Area of circle= πr²

Substitute: π(5)²

Solution: 25π or about 78.5 cm²

You might be interested in

Evaluate the definite integral. 1/4 csc(2πt) cot(2πt) dt 1/12

Afina-wow [57]

Hey there, hope I can help!

$\frac{1}{4}\csc \left(2\pi t\right)\cot \left(2\pi t\right)dt\frac{1}{12}$

$\mathrm{Multiply\:fractions}: \:a\cdot \frac{b}{c}\cdot \frac{d}{e}=\frac{a\:\cdot \:b\:\cdot \:d}{c\:\cdot \:e} \ \textgreater \ \frac{1\cdot \:1\cdot \:dt}{4\cdot \:12}\csc \left(2\pi t\right)\cot \left(2\pi t\right)$

$\mathrm{Apply\:rule}\:1\cdot \:a=a \ \textgreater \ \frac{dt}{4\cdot \:12}\csc \left(2\pi t\right)\cot \left(2\pi t\right)$

$\mathrm{Multiply\:the\:numbers:}\:4\cdot \:12=48 \ \textgreater \ \frac{dt}{48}\csc \left(2\pi t\right)\cot \left(2\pi t\right)$

$\mathrm{Multiply\:fractions}: \:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c} \ \textgreater \ \frac{dt\csc \left(2\pi t\right)\cot \left(2\pi t\right)}{48}$

Hope this helps!

5 0

3 years ago

If the altitude of an isosceles right triangle has a length of x units, what is the length of one leg of the large right triangl

EleoNora [17]

The answer is B. 2 units HOPE IT HELPS

4 0

3 years ago

Read 2 more answers

Its timed hurry lad <br> Evaluate the logarithm log8 (32)

tiny-mole [99]

It is 5/3 !! 8^(5/3)=....32!

7 0