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hram777 [196]
3 years ago
12

What advantage does a 4-in. octagon box have over a 3¼-in. octagon box?

Mathematics
1 answer:
weeeeeb [17]3 years ago
5 0
Is that the whole question?  What kind of advantage are we talking about here?

One possibility would be that the 4-inch box has a greater volume (capacity) than does the 3 1/4-in box.  If that's the question here, then your job  is to calculate the difference in volume.  Find the vol. of each box and subtract the smaller from the larger to calculate the "size advantage" or "volume advantage."

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The YMCA lap pool is a right rectangular prism 36.8\, \text{m}36.8m36, point, 8, start text, m, end text long by 20 \,\text{m}20
PilotLPTM [1.2K]

Volume is a three-dimensional scalar quantity. The depth of the YMCA lap pool is 2 meters.

<h3>What is volume?</h3>

A volume is a scalar number that expresses the amount of three-dimensional space enclosed by a closed surface.

Given that the following details about the YMCA lap pool:

  • The volume of the pool = 1472m³
  • The length of the pool = 36.8m
  • The width of the pool = 20 m

Since the pool is in the space of a right rectangular prism, therefore, the volume of the prism will be the product of length, width and depth. Therefore, the volume of the pool can be written as,

The volume of the pool = Length × width × depth

1472m³ = 36.8m × 20 m × depth of the pool

Depth of the pool = (1472m³ ) / (36.8m × 20m)

                              = 2 meter

Hence, the depth of the YMCA lap pool is 2 meters.

Learn more about Volume here:

brainly.com/question/13338592

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3 0
1 year ago
I need HELPPPPPP PLEASEEEEEE!!!!!!!!~!!!!!!
Sedaia [141]

Answer:

Starting from the left.

4 × 3

5 × 5

2 × 5

4 × 5

4 × 4

1.5 × 2

Step-by-step explanation:

Divide all dimensions by 8.

5 0
3 years ago
Jim Tree will drive from his home in Jackson Heights to Jones City. The distance on the map measures 3 1/2 inches. The scale on
expeople1 [14]
Just multiply !!

so 1 inch = 5 miles
3.5 inch must be 3.5×5 = 17.5 miles

so the answer is 17.5 miles !!
7 0
3 years ago
Read 2 more answers
Substitute (= 3 and 1-6 to determine if the two expressions are equivalent.
mezya [45]

Answer:a b d

Step-by-step explanation:

4 0
3 years ago
A triangle has side lengths of 9 in, 13 in, and 20 in. What is the measurement of this triangle's largest angle?
Rama09 [41]

1. Given any triangle ABC with sides BC=a, AC=b and AB=c, the following are true :

     i) the larger the angle, the larger the side in front of it, and the other way around as well. (Sine Law) Let a=20 in, then the largest angle is angle A.

      ii) Given the measures of the sides of a triangle. Then the cosines of any of the angles can be found by the following formula:

       a^{2}=b ^{2}+c ^{2}-2bc(cosA)

2.

20^{2}=9 ^{2}+13 ^{2}-2*9*13(cosA)&#10;&#10;400=81+169-234(cosA)   150=-234(cosA)&#10;&#10;cosA=150/-234= -0.641

3. m(A) = Arccos(-0.641)≈130°,

4. Remark: We calculate Arccos with a scientific calculator or computer software unless it is one of the well known values, ex Arccos(0.5)=60°, Arccos(-0.5)=120° etc

6 0
3 years ago
Read 2 more answers
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