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Anni [7]
3 years ago
7

Write the equation of the line that passes through(-2,1)and is prependicular of the line 3x-2y=5

Mathematics
1 answer:
almond37 [142]3 years ago
6 0
The equation is y=-2/3x-1/3 i think

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0=9x-9x<br> no solution,<br> one solution,<br> infinite solutions
attashe74 [19]

Answer:

0 = 9x - 9x

0 = 0

This means it has infinite number of solutions.

Step-by-step explanation:

<h2>HOPE IT HELPS U!!!!</h2>
4 0
2 years ago
Please HELP!! ILL GIVE BRAINLEST! QUCIK PLEASE HELP!!
Elena-2011 [213]

Answer:

d. linear; $25/hour

Step-by-step explanation:

From looking at the graph, we have that renting for 2 hours costs $50, for 4 hours costs $100, for 6 hours costs $150, and for 8 hours costs $200. To find out whether the quantities described in the table are linear, we have to see if there is a constant rate of change of price.

For hour 2 to hour 4, we can see that the price increases by $50. This is the same for hour 4 to hour 6 and hour 6 to hour 8. For every 2 hour time interval, the price increases by $50. Therefore, there is a constant rate of change and the quantities described in the table are linear.

Now we have to find the constant rate of change per hour. We know that the price increases by $50 every 2 hours, so, by dividing both the hours and price increase by 2, the price increases by $25 per hour. So the constant rate of change is $25/hour.

Linear. $25/hour

Answer choice d.

I hope you find my answer and explanation to be helpful. Happy studying.

6 0
3 years ago
The plane x+y+2z=8 intersects the paraboloid z=x2+y2 in an ellipse. Find the points on this ellipse that are nearest to and fart
DiKsa [7]

Answer:

The minimum distance of   √((195-19√33)/8)  occurs at  ((-1+√33)/4; (-1+√33)/4; (17-√33)/4)  and the maximum distance of  √((195+19√33)/8)  occurs at (-(1+√33)/4; - (1+√33)/4; (17+√33)/4)

Step-by-step explanation:

Here, the two constraints are

g (x, y, z) = x + y + 2z − 8  

and  

h (x, y, z) = x ² + y² − z.

Any critical  point that we find during the Lagrange multiplier process will satisfy both of these constraints, so we  actually don’t need to find an explicit equation for the ellipse that is their intersection.

Suppose that (x, y, z) is any point that satisfies both of the constraints (and hence is on the ellipse.)

Then the distance from (x, y, z) to the origin is given by

√((x − 0)² + (y − 0)² + (z − 0)² ).

This expression (and its partial derivatives) would be cumbersome to work with, so we will find the the extrema  of the square of the distance. Thus, our objective function is

f(x, y, z) = x ² + y ² + z ²

and

∇f = (2x, 2y, 2z )

λ∇g = (λ, λ, 2λ)

µ∇h = (2µx, 2µy, −µ)

Thus the system we need to solve for (x, y, z) is

                           2x = λ + 2µx                         (1)

                           2y = λ + 2µy                       (2)

                           2z = 2λ − µ                          (3)

                           x + y + 2z = 8                      (4)

                           x ² + y ² − z = 0                     (5)

Subtracting (2) from (1) and factoring gives

                     2 (x − y) = 2µ (x − y)

so µ = 1  whenever x ≠ y. Substituting µ = 1 into (1) gives us λ = 0 and substituting µ = 1 and λ = 0  into (3) gives us  2z = −1  and thus z = − 1 /2 . Subtituting z = − 1 /2  into (4) and (5) gives us

                            x + y − 9 = 0

                         x ² + y ² +  1 /2  = 0

however, x ² + y ² +  1 /2  = 0  has no solution. Thus we must have x = y.

Since we now know x = y, (4) and (5) become

2x + 2z = 8

2x  ² − z = 0

so

z = 4 − x

z = 2x²

Combining these together gives us  2x²  = 4 − x , so

2x²  + x − 4 = 0 which has solutions

x =  (-1+√33)/4

and

x = -(1+√33)/4.

Further substitution yeilds the critical points  

((-1+√33)/4; (-1+√33)/4; (17-√33)/4)   and

(-(1+√33)/4; - (1+√33)/4; (17+√33)/4).

Substituting these into our  objective function gives us

f((-1+√33)/4; (-1+√33)/4; (17-√33)/4) = (195-19√33)/8

f(-(1+√33)/4; - (1+√33)/4; (17+√33)/4) = (195+19√33)/8

Thus minimum distance of   √((195-19√33)/8)  occurs at  ((-1+√33)/4; (-1+√33)/4; (17-√33)/4)  and the maximum distance of  √((195+19√33)/8)  occurs at (-(1+√33)/4; - (1+√33)/4; (17+√33)/4)

4 0
3 years ago
Bart's drive to the airport takes 232323 minutes. What is the latest time Bart can leave to arrive at the airport by a quarter b
Nikitich [7]
It take 23 mins for the drive

He needs to reach the airport by a quarter before 6

a quarter before 6 = 5.45
So he needs to leave 23 mins before 5.45

23 mins before 5.45 = 5.22
6 0
3 years ago
Please solve the complex number by finding the complex conjugate.Correct answer will get brainliest!
jasenka [17]

-2 - 2i*square root of 11/483

6 0
2 years ago
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