Assuming we need to find i such that
1 ≤ i ≤ n and t[i]=i.
If we need to find only the first occurrence, we can do:
for i:1 to n {
if t[i]=i then return(i)
}
If exhaustive search is required, then put the results (values of i) in an array or a linked list, return the number of values found, and the array (or linked list).
Let's solve your system by substitution.
a=−2;b=−3
Step: Solve a=−2for a:
a=−2
Step: Substitute−2for a in b=−3:
b=−3
b=−3
Answer:
a=−2 and b=−3
Answer:
X=4
Step-by-step explanation:
2÷\frac{1}{2}=4
Answer: 4.25.
Step-by-step explanation:
First subtract 13.09 from the 21.59, giving you 8.5 as the leftover space on the page.
Then divide in half to find the left and right margin.
Answer:
The investment earns either 180 or 720. I'm not exactly sure.