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Komok [63]
3 years ago
3

Two race cars, Car X and Y, are at the starting point of a 2km track at the same time. Car X and Car Y make one lap every 60s an

d every 80s respectively. How long, in minutes, will it take for the faster car to be 5 laps ahead of the slower car?
Mathematics
1 answer:
Artemon [7]3 years ago
7 0

Answer:

It will take the faster car 15 minutes to be 5 laps ahead of the slower car.

Step-by-step explanation:

Car X is faster than Car Y.

Car X makes 1 lap in 60 seconds.

Car Y makes 1 lap in 80 second.

This means Car X is 20 seconds faster than Car Y.

It also mean that Car X needs only three 20 seconds to be 1 lap ahead of Car Y. But Car X can only accumulate 60 seconds after 3 laps.

So, Car X is 1 lap ahead after every 3 laps.

Car X will be 5 laps ahead by (3×5)th lap or 15th lap.

It will take Car X (15 × 60) seconds to be 5 laps ahead of Car Y.

15 × 60 = 900 seconds

900 seconds = 900/60 minutes

= 15 minutes.

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In a race , Ram covers 5 km in 20 min. How much distance will he cover in 100 min ?
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Step-by-step explanation:

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Determine the value of x in the figure. answers: A) x = 90 B) x = 40 C) x = 45 D) x = 135
guapka [62]

Answer:

Please mark be brainliest and I hoped this helped!

x = 45°

Step-by-step explanation:

Since this is an isosceles triangle, that means that x, and the angle opposite from x, are the same. We take 135° and subtract that from 180°. That gives us 45°. Since the angle opposing x is 45°, then x is 45° as well.

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3 years ago
Read 2 more answers
Solve x + 3y = 9<br> 3x – 3y = -13 (1 point)
zavuch27 [327]

Answer:

(-1, 10/3)

x = -1

y = 10/3

Step-by-step explanation:

To solve a system, one of the methods you can use is <u>elimination</u>. To use elimination, you need <u>a variable to have the same coefficient in BOTH equations</u>. Since both equations have "3y", with the same coefficient (3), we can use this method.

We want to eliminate a variable by cancelling it out. Since positive 3y PLUS negative 3y is 0, the variable in eliminated. ADD each of the terms in the equations together.

.        x + 3y = 9

<u>+    3x – 3y = -13</u>

.     4x – 0y = -4           3y - 3y = 0        

.             4x = -4            Divide both sides by 4 to isolate 'x'

.               x = -1              Solved for the x-coordinate

Since we know one variable, 'x', we can easily find the other, 'y'. Substitute 'x' with -1 in any of the equations. Then, isolate 'x'.

x + 3y = 9

(-1) + 3y = 9

-1 + 1 + 3y = 9 + 1      Add 1 to both sides to cancel out left side.

3y = 9 + 1          Add on the right side (9 + 1 = 10)

3y = 10              Divide both sides by 3 to isolate 'y'

y = 10/3             Solved for the y-coordinate

Put the 'x' and 'y' coordinates together in an ordered pair, which you write as (x, y).

The solution to the system is (-1, 10/3).

5 0
3 years ago
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