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dmitriy555 [2]
3 years ago
12

WHATS THE ANSWER?? (QUESTION BELOW)

Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
6 0

Answer:

a) 10 combinations

b) (10p,1p), (10p,50p), (10p,2p), (10p,20p), (1p,50p), (1p,2p), (1p,20p), (50p,2p), (50p,20p), (2p,20p)

Step-by-step explanation:

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A clock strikes 3;00. At what time between 3 and 4 will the needles overlap.​
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180/11

Step-by-step explanation:

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Aaron scored 452.65 marks out of 600 in the final examination. How many marks did he lose?
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Answer:

He lost 147.35 marks

Step-by-step explanation:

Take the total marks and subtract the marks he got to find the marks he lost

600-452.65= 147.35

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Jeremiah recorded the temperatures for
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C

Step-by-step explanation:

I believe it is C. If the temperature dropped, it means it went down, so a negative option makes sense. To check, use the process of elimination.

A: The temperature dropped, not rose.

B: It only dropped 15 degrees, not 151.

D: It dropped, not rose, and only dropped 15 degrees.

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A sequence is defined by the recursive function if f(1)=10 what is f(3)
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4 years ago
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Your firm wants to investigate how much money the typical tourist will spend on their next visit to New York? How many tourists
dimaraw [331]

Answer:

n=(\frac{2.58(59)}{20})^2 =57.93

And if we round up the answer we see that the value of n to ensure the margin of error required \pm=20 $ is n=58.

C) 58

Step-by-step explanation:

Assuming this :"Your firm wants to investigate how much money the typical tourist will spend on their next visit to New York. How many tourists should be included in your sample if you want to be 99% confident that the sample mean is within $20 from the population mean? From previous studies, we know that the standard deviation is $59."

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Assuming the X follows a normal distribution

X \sim N(\mu, \sigma=59)

We know that the margin of error for a confidence interval is given by:

Me=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

The next step would be find the value of \z_{\alpha/2}, \alpha=1-0.99=.01 and \alpha/2=0.005

Using the normal standard table, excel or a calculator we see that:

z_{\alpha/2}=2.58

If we solve for n from formula (1) we got:

\sqrt{n}=\frac{z_{\alpha/2} \sigma}{Me}

n=(\frac{z_{\alpha/2} \sigma}{Me})^2

And we have everything to replace into the formula:

n=(\frac{2.58(59)}{20})^2 =57.93

And if we round up the answer we see that the value of n to ensure the margin of error required \pm=20 $ is n=58.

C) 58

6 0
3 years ago
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