Its a type of thermal expansion and described by fractions that represents the fractional increase length of a thin beam of a material exposed to its temperature increase of one degree celcious,"
Answer:
50% duhh
Step-by-step explanation:
25% is also a equation
Well what I would do first is divide the 900 student by the 445 teacher to get 20 students per teacher. Now I would take that 20 and multiply it by 110 teacher to get 2200 Students.
Answer= C) 2200 Students
Answer:
Construct MN.
Since M is the midpoint of OA, OM = MA
Similarly, N is the midpoint of OB.
Thus, ON = NB.
Now, in Δs OMN and OAB,
∠MON = ∠AOB (common angle)
(sides are in proportional ratio; OA = 2OM and OB = 2ON)
∴ Δs OMN and OAB are similar (2 sides are in proportion, with the included angle)
Since they are similar, then ∠OMN = ∠OAB (corresponding angles of similar triangles are equal)
But since ∠OMN = ∠OAB, then that means MN || AB (corresponding angles of two lines must be equal since they also sit relative to the transverse line, OA)
Thus, AB || MN (QED)