Answer:
The word "ARRANGE" can be arranged in
2!×2!
7!
=
4
5040
=1260 ways.
For the two R's do occur together, let us make a group of R's taking from "ARRANGE" and permute them.
Then the number of ways =
2!
6!
=360.
The number ways to arrange "ARRANGE", where two "R's" will not occur together is =1260−360=900.
Also in the same way, the number of ways where two "A's" are together is 360.
The number of ways where two "A's" and two "R's" are together is 5!=120.
The number of ways where neither two "A's" nor two "R's" are together is =1260−(360+360)+120=660.
Step-by-step explanation:
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Answer:
1.5
Step-by-step explanation:
Anything divided by 1 is itself
The correct answer is: [C]: " 5 " .
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→ " a = 5 " .
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Explanation:
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Given: " a + 1 <span>− 2 = 4 " ; Solve for "a" ;
4 + 2 = 6 ;
6 </span>− 1 = 5 ; → a = 5 ;
To check our work:
5 + 1 − 2 = ? 4 ?? ;
5 + 1 = 6 ;
6 − 2 = 4. Yes!
So the answer is: [C]: " 5 ".
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→ " a = 5 " .
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Answer:
B
Step-by-step explanation: