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3 years ago

URGENT PLEASE HELP ME ASAP, ITS DUE TODAY!!!

Mathematics

1 answer:

vladimir2022 [97]3 years ago

8 0

Answer:

Construct MN.

Since M is the midpoint of OA, OM = MA

Similarly, N is the midpoint of OB.

Thus, ON = NB.

Now, in Δs OMN and OAB,

∠MON = ∠AOB (common angle)

(sides are in proportional ratio; OA = 2OM and OB = 2ON)

∴ Δs OMN and OAB are similar (2 sides are in proportion, with the included angle)

Since they are similar, then ∠OMN = ∠OAB (corresponding angles of similar triangles are equal)

But since ∠OMN = ∠OAB, then that means MN || AB (corresponding angles of two lines must be equal since they also sit relative to the transverse line, OA)

Thus, AB || MN (QED)

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The coordinates of the points M, N, P, and Q are -11, 32, -15, and 17, respectively. Which point is closest to the origin?

kompoz [17]

Answer:

i think is M so -11

have a nice day! (^o^)

8 0

3 years ago

Suppose you have 5 riders and 5 horses, and you want to pair them off so that every rider is assigned one horse (and no horse is

maw [93]

There are 120 ways in which 5 riders and 5 horses can be arranged.

We have,

5 riders and 5 horses,

Now,

We know that,

Now,

Using the arrangement formula of Permutation,

i.e.

The total number of ways $^nN_r = \frac{n!}{(n-r)!}$ ,

So,

For n = 5,

And,

r = 5

As we have,

n = r,

So,

Now,

Using the above-mentioned formula of arrangement,

i.e.

The total number of ways $^nN_r = \frac{n!}{(n-r)!}$ ,

Now,

Substituting values,

We get,

$^5N_5 = \frac{5!}{(5-5)!}$

We get,

The total number of ways of arrangement = 5! = 5 × 4 × 3 × 2 × 1 = 120,

So,

There are 120 ways to arrange horses for riders.

Hence we can say that there are 120 ways in which 5 riders and 5 horses can be arranged.

Learn more about arrangements here

brainly.com/question/15032503

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7 0

2 years ago

Which one is correct? in need of large help

Oksanka [162]

Answer:

Option C. x + 12 ≤ 2(x – 3)

Step-by-step explanation:

From the question, we obtained the following information:

x + 12 ≤ 5 – y .......(1)

5 – y ≤ 2(x – 3) ....... (2)

To know which option is correct, do the following:

From equation 2,

5 – y ≤ 2(x – 3)

Thus, we can say

5 – y = 2(x – 3)

Now, we shall substitute the value of 5 – y into equation 1 as shown below:

x + 12 ≤ 5 – y

5 – y = 2(x – 3)

x + 12 ≤ 2(x – 3)

From the above illustration, we can see that if x + 12 ≤ 5 – y and 5 – y ≤ 2(x – 3), then x + 12 ≤ 2(x – 3) must be true.

Option C gives the correct answer.

6 0

4 years ago

A?<br> B?<br> C?<br> B?<br> I need help

Illusion [34]

What’s the answer and questions

6 0

4 years ago

Solve linear equation . I also have to graph it

Andrews [41]

Answer:

This type of linear equations cannot be solved.

Step-by-step explanation:

5 0

4 years ago

***URGENT*** PLEASE HELP ME ASAP, ITS DUE TODAY!!!

URGENT PLEASE HELP ME ASAP, ITS DUE TODAY!!!