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3 years ago

Help me please with number 2.a and 2.b

Mathematics

1 answer:

elixir [45]3 years ago

6 0

It's GT and jhj o by hand hxn jxnxn

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Find the product of 3x and x^2-4x+10 subtract x^3+7x^2-2x

Virty [35]

Answer:

below

Step-by-step explanation:

$2x^3 -5x^2 +28x$

I'm pretty sure this is the answer.

7 0

3 years ago

Amrita bought a new delivery van for $32,500. The value of this van depreciates at a rate of 12% each year. Write a function f(x

FrozenT [24]

Answer:

The function, f(x) to model the value of the van can be expressed as follows;

$f(x) = 32,500 \times \left(0.88\right)^x$

Step-by-step explanation:

From the question, we have;

The amount at which Amrita bought the new delivery van, PV = $32,500

The annual rate of depreciation of the van, r = -12% per year

The Future Value, f(x), of the van after x years of ownership can be given according to the following formula

$f(x) = PV \cdot \left(1 + \dfrac{r}{100} \right)^x$

Therefore, the function, f(x) to model the value of the van after 'x' years of ownership can be expressed as follows;

$f(x) = 32,500 \cdot \left(1 - \dfrac{12}{100} \right)^x = 32,500 \cdot \left(0.88\right)^x$

8 0

3 years ago

Nancy has a big chocolate bar shaped like a rectangular prism. It is 15 centimeters long, 14 centimeters wide, and 2 centimeters

Leya [2.2K]

Answer: $420 cm^{3}$

Step-by-step explanation:

The volume $V$ of a rectangular prism is given by:

$V=(length)(width)(thickness)$

If the chocolate bar has the following dimensions:

$length=15 cm$

$width=14 cm$

$thickness=2 cm$

Its volume is:

$V=(15 cm)(14 cm)(2 cm)$

$V=420 cm^{3}$

4 0

3 years ago

Water stations will be placed every 600 meters of a fifteen kilometer race how many water stations will be needed

zaharov [31]

15 km = 15,000 m
every 600 m, there is one water station (starting point at 600 m)
number of stations needed : 15000/600 = 25 water stations

3 0

3 years ago

2x^3 + 3x^2 -11x -6 divided by x - 2

Gnesinka [82]

p(x)= x-2

g(x)= 2x^3 + 3x^2 - 11x - 6

first we have to find the zero of the polynomial of x-2

p(x)= x-2 = 0

x=2

therefore,

p(x)= 2x^3 + 3x^2 - 11x - 6

p(2)= 2*2^3 + 3*2^2 - 11*2 - 6

= 2*8 + 3*4 - 11*2 - 6

= 16 + 12 - 22 - 6

= 28-28

= 0

Hope it helped u, ^_^.

3 0

3 years ago