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frutty [35]
3 years ago
11

Megan sent 12 postcards last week. This week she sent 4 postcards. How many more postcards didn't she sent last week?

Mathematics
2 answers:
choli [55]3 years ago
7 0

Answer:

She sent 8 more postcards last week.

Step-by-step explanation:

Consider the provided information.

Megan sent 12 postcards last week. This week she sent 4 postcards.

We need to find How many more postcards did she sent last week?

To find this simply subtract the numbers as shown:

12-4 = 8

Hence, she sent 8 more postcards last week.

Gala2k [10]3 years ago
5 0
8 postcards she didn't sent last week.
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-3a + b when a<br> =<br> -4 and b = 9.
Archy [21]

Answer:

12+9=21

Step-by-step explanation:

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3 years ago
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Find the area of the shaded sector. PLZ HELP!:)
Strike441 [17]

Answer:

Area of whole circle, i.e. 360 degrees = π(8.91)(8.91) = 79.3881 sq. cm

Area of 1 degree = 0.2205225 sq.cm.

Area of 81 degrees = 17.8623225 sq.cm.

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3 years ago
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Please help with this question
LuckyWell [14K]

9514 1404 393

Answer:

  4. (d) 4.38 in³

  5. (b) 19 gallons

  6. (a) 6.4 yd³

Step-by-step explanation:

4. The equation can be rearranged to find the compressed volume.

Multiply both sides by the compressed volume:

  (compression ratio)×(compressed volume) = (expanded volume)

Divide both sides by the compression ratio:

  (compressed volume) = (expanded volume)/(compression ratio)

Fill in the numbers and do the arithmetic.

  compressed volume = 46.0 in³/(10.5/1) = 4.38 in³

The compressed volume is about 4.38 in³.

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5. The area to be covered is 3170 ft². We want to cover it twice, so the total area we want to cover is 2×3170 ft² = 6340 ft². One gallon of paint covers 350 ft². We want to find the smallest integer number of gallons n such that ...

  n×(350 ft²) ≥ 6340 ft²

Dividing by the coefficient of n, we have ...

  n ≥ 6340/350 ≈ 18.11

The smallest integer value of n is 19. 19 gallons of paint will be needed.

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6. The quantity of sand needed (q) is proportional to the area to be covered, so we have ...

  q/(400 yd²) = (1.6 yd³)/(100 yd²)

Multiplying both sides of this equation by 400 yd² gives ...

  q = (1.6 yd³)(400/100) = 6.4 yd³

6.4 yd³ of sand will be needed.

8 0
3 years ago
70 sixth-graders had an average weight of 90 pounds. 30 seventh graders had an average weight of 100 pounds. What was the averag
Brrunno [24]

We know that 70 sixth graders had an average weight of 90 pounds, and 30 seventh graders had an average weight of 100 pounds.

We know that the weight of all 70 sixth graders will be 70*90, since we're multiplying the total amount of students by the average.

Using this same logic tells us that the total weight for the 30 seventh graders is 30*100

The average weight for all 100 students will be the total weight of the sixth graders (which is 70*90) added with the total weight of the seventh graders (which is 30*100), then finally divided by the total amount of students in the sample space (which is 100).

\dfrac{70(90)+30(100)}{100}

=\dfrac{6300+3000}{100}

=\dfrac{9300}{100}

=93

The average of all 100 students is 93 pounds.

Let me know if you need any clarifications, thanks!

6 0
4 years ago
A pizza has 3 toppings with no toppings overlapping. Pepperoni tops 1/3 of the pizza and mushroom top 2/5. The rest is topped wi
Bond [772]
\frac{1}{3} + \frac{2}{5} + x=1&#10;
x= 1- \frac{5}{15} - \frac{6}{15} = \frac{15}{15} - \frac{11}{15} = \frac{4}{15}
Answer: Sausage tops \frac{4}{15} of the pizza
3 0
4 years ago
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