A stadium manager spends $50,000 on TV ads and $37,000 on cable TV ads. What percentage of his advertising expenditures is spent
2 answers:
Answer:
42.52%
Step-by-step explanation:
A stadium manager spends $50,000 on TV ads and $37,000 on cable TV ads.
We need to find the percentage of advertising expenditure on cable TV
First we find total expenditure on advertising,
Total expenditure = 50,000 + 37,000
= $87,000
Expenditure spent on cable TV = $37,000
Formula:
Hence, 42.52% of his advertising expenditure is spent on cable TV
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Answer:
x=-3 x=-1 x=2 x=-2
Step-by-step explanation:
p(x) = (x^2 + 4x + 3)(x^2 – 4)
Set this equal to zero to find the x intercepts
0 = (x^2 + 4x + 3)(x^2 – 4)
Using the zero product property
(x^2 + 4x + 3) =0 (x^2 – 4) =0
Factor
(x+3)(x+1) =0 (x-2) (x+2)=0
Using the zero product property
x+3 =0 x+1 =0 x-2 =0 x+2 =0
x=-3 x=-1 x=2 x=-2
