A stadium manager spends $50,000 on TV ads and $37,000 on cable TV ads. What percentage of his advertising expenditures is spent
2 answers:
Answer:
42.52%
Step-by-step explanation:
A stadium manager spends $50,000 on TV ads and $37,000 on cable TV ads.
We need to find the percentage of advertising expenditure on cable TV
First we find total expenditure on advertising,
Total expenditure = 50,000 + 37,000
= $87,000
Expenditure spent on cable TV = $37,000
Formula:
Hence, 42.52% of his advertising expenditure is spent on cable TV
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Answer:
x = 3 + √6 ; x = 3 - √6 ; ;
Step-by-step explanation:
Relation given in the question:
(x² − 6x +3)(2x² − 4x − 7) = 0
Now,
for the above relation to be true the following condition must be followed:
Either (x² − 6x +3) = 0 ............(1)
or
(2x² − 4x − 7) = 0 ..........(2)
now considering the equation (1)
(x² − 6x +3) = 0
the roots can be found out as:
for the equation ax² + bx + c = 0
thus,
the roots are
or
or
and, x =
or
and, x =
or
x = 3 + √6 and x = 3 - √6
similarly for (2x² − 4x − 7) = 0.
we have
the roots are
or
or
and, x =
or
and, x =
or
and, x =
or
and,
Hence, the possible roots are
x = 3 + √6 ; x = 3 - √6 ; ;