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Studentka2010 [4]
3 years ago
15

PLEASE DRAW A GRAPH WITH THIS USING THE Exponential Functions HURRY

Mathematics
1 answer:
AleksAgata [21]3 years ago
7 0

Answer:

bd=cc=oc2

Step-by-step explanation:

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Find the equation of the vertical line through (7,-3)
wlad13 [49]
X = 7
Is a vertical line that passes through (7,-3).
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3 years ago
What is the smallest whole number that is a multiple of 5, 9, and 12?
Marianna [84]

Answer:180

Step-by-step explanation:

you start by finding the prime factorization of the number

5=1*5

9=3*3

12=2*2*3

the shortest way to find the factors is to find is most of them like example, at max, there are 2 two's, 2 three's and 1 five then you multiply them all together

4*9*5=180 and that's the answer

7 0
3 years ago
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PLEASE HELP!!!!
Artyom0805 [142]

Answer:

The total cost of producing 6 widgets is $231.

Step-by-step explanation:

5 0
3 years ago
List the angles of the triangle in order from<br> largest to smallest.
alina1380 [7]

Answer: A, C, B

Step-by-step explanation:

Because "a" has 8 across

And "c" has 10 across

and "b" has 13 across

7 0
3 years ago
An urn contains nine red and one blue balls. A second urn contains one red and five blue balls. One ball is removed from each ur
il63 [147K]

Answer:

0.362

Step-by-step explanation:

When drawing randomly from the 1st and 2nd urn, 4 case scenarios may happen:

- Red ball is drawn from the 1st urn with a probability of 9/10, red ball is drawn from the 2st urn with a probability of 1/6. The probability of this case to happen is (9/10)*(1/6) = 9/60 = 3/20 or 0.15. The probability that a ball drawn randomly from the third urn is blue given this scenario is (1 blue + 5 blue)/(8 red + 1 blue + 5 blue) = 6/14 = 3/7.

- Red ball is drawn from the 1st urn with a probability of 9/10, blue ball is drawn from the 2nd urn with a probability of 5/6. The probability of this event to happen is (9/10)*(5/6) = 45/60 = 3/4 or 0.75. The probability that a ball drawn randomly from the third urn is blue given this scenario is (1 blue + 4 blue)/(8 red + 1 blue + 1 red + 4 blue) = 5/14

- Blue ball is drawn from the 1st urn with a probability of 1/10, blue ball is drawn from the 2nd urn with a probability of 5/6. The probability of this event to happen is (1/10)*(5/6) = 5/60 = 1/12. The probability that a ball drawn randomly from the third urn is blue given this scenario is (4 blue)/(9 red + 1 red + 4 blue) = 4/14 = 2/7

- Blue ball is drawn from the 1st urn with a probability of 1/10, red ball is drawn from the 2st urn with a probability of 1/6. The probability of this event to happen is (1/10)*(1/6) = 1/60. The probability that a ball drawn randomly from the third urn is blue given this scenario is (5 blue)/(9 red + 5 blue) = 5/14.

Overall, the total probability that a ball drawn randomly from the third urn is blue is the sum of product of each scenario to happen with their respective given probability

P = 0.15(3/7) + 0.75(5/14) + (1/12)*(2/7) + (1/60)*(5/14) = 0.362

8 0
3 years ago
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