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Vesnalui [34]
3 years ago
13

the histogram on the left shows the number of hours students in an art class practiced drawing during one week.​

Mathematics
1 answer:
svet-max [94.6K]3 years ago
4 0

Step-by-step explanation:

mmm Next no se...........

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Since 1980 the average height of 20-year-old females has increased by 2.3 cm, to 170.6 cm. What was the average height of a 20-y
marusya05 [52]

Answer:

168.3 cm

Step-by-step explanation:

It was 2.3 cm less than 170.6 cm, so we use subtraction.

170.6 cm - 2.3 cm = 168.3 cm

3 0
2 years ago
Can some one help me with this please
Nastasia [14]

Answer:

In order to help with this problem, I need to see part a.

Step-by-step explanation:


7 0
3 years ago
HELP ILL GIVE BRAINLIEST
Nikitich [7]

Problem 1

To begin with, Aldi has 0 mg of the medicine in his bloodstream.

Then Haidar gives her dog 150 mg of the medicine.

The day progresses along and at the end of the day, 40% of the medicine remains. So 0.40*150 = 60 mg remains.

At the start of day 2, Haidar gives another 150 mg dose. The 60 mg bumps up to 60+150 = 210 mg. This becomes 0.40*210 = 84 mg at the end of day 2.

At the start of day 3, she gives her dog yet another 150 mg dose. So the 84 increases to 84+150 = 234. This decays to 0.40*234 = 93.6 mg at the end of day 3.

Finally, at the start of day 4, the 150 mg dose bumps the 93.6 up to 93.6+150 =  243.6 mg, which then decays to 0.40*243.6 = 97.44 mg.

Here's a table to summarize everything

\begin{array}{|c|c|c|c|} \cline{1-4}
& \text{Start} & \text{When meds are given} & \text{End}\\ \cline{1-4}
\text{Day} & \text{x} & \text{y = 150+x} & \text{z = 40\% of y }\\ \cline{1-4}
\text{1} & \text{0} & \text{150} & \text{60}\\ \cline{1-4}
\text{2} & \text{60} & \text{210} & \text{84}\\ \cline{1-4}
\text{3} & \text{84} & \text{234} & \text{93.6}\\ \cline{1-4}
\text{4} & \text{93.6} & \text{243.6} & \text{97.44}\\ \cline{1-4}
\end{array}\\
\text{All values in the table are amounts in mg}

================================================

Problem 2

The first term is a_1 = 0 to indicate the dog has 0 mg of medicine in his bloodstream to start off with.

Then we add on 150 mg to that amount, and take 40% of the sum.

This indicates that a_2 = 0.40(150+a_1)

Similarly,

a_3 = 0.40(150+a_2)

and so on.

In general, we have this recursive definition

\begin{cases}
a_1 = 0\\
a_n = 0.40(150+a_{n-1})
\end{cases}

The a_n refers to the nth dose while a_{n-1} is the dose amount just before the nth dose.

This sequence is neither arithmetic nor geometric.

It's not arithmetic because we aren't adding the same number to each term to get the next term. It's not geometric because we aren't applying the same common ratio to multiply from term to term.

The mix of "plus 150" and "times 0.40" is almost like this is a hybrid of arithmetic and geometric respectively. However, it's not purely one or the other.

3 0
2 years ago
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17minus negative12 minus22
Gnesinka [82]
-17 would be the answer
5 0
4 years ago
Read 2 more answers
The length of life of an instrument produced by a machine has a normal distribution with a mean of 12 months and standard deviat
Vikentia [17]

Answer:

solved

Step-by-step explanation:

Mean = 12

SD = 2

Answer to part 2)  Less than 7 months

P(x < 7)

P(x < 7) = P(z < (7-12)/2) = P(z < -2.5)

This probability can be obtained by referring to the Z table

Thus P(x < 7) = 0.0062

1) Between 7 and 12 months

P(7 < x < 12) = P( x< 12) - P(x < 7)

We have P(x < 12) = 0 ......[because mean = 12]

and P(x < 7) = 0.0062 ...[this we got is part a]

Thus on plugging these values we get

P( 7 < x < 12) = 0.5 - 0.0062 = 0.4938

Thus P(7 < x < 12) = 0.4938

3

6 0
3 years ago
Read 2 more answers
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