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3 years ago

7

What is an advantage of the correlation coefficient over the covariance?

1 answer:

Fofino [41]3 years ago

7 0

The advantage of the correlation measure over the covariance measure is that correlation is unit-free but covariance is not. Covariance is sensitive to the values of x and y. The correlation coefficient has <span>been normalized and is unit-free.</span>

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I don’t understand this at all

LUCKY_DIMON [66]

Answer:

I think the answer is - 2 + ( 3/4) =2 3/4

Step-by-step explanation:

first of all we can take out the =-1 1/4 and - 1 3/4 email it's not it the correct place also - 2 1/4 because of the 1/4

4 0

3 years ago

The area of the sandbox is 56 2/3 square feet. The width is 8 1/2 feet. What is the length? Hint: Divide area by length

sertanlavr [38]

Answer:

20/3 ft or 6 2/3 ft

Step-by-step explanation:

A = 56 2/3 sq ft

W = 8 1/2 ft

L = ?

A = LW

L = A/W

$L = \dfrac{A}{W}$

$L = \dfrac{56~\frac{2}{3}~sq~ft}{8~\frac{1}{2}~ft}$

Change the mixed numbers into fractions.

$a\frac{b}{c} = \dfrac{ac + b}{c}$

$L = \dfrac{\frac{56 \times 3 + 2}{3}}{\frac{8 \times 2 + 1}{2}}$

$L = \dfrac{\frac{170}{3}}{\frac{17}{2}}$

$L = \dfrac{170}{3} \div \dfrac{17}{2}$

$L = \dfrac{170}{3} \times \dfrac{2}{17}$

$L = \dfrac{170 \times 2}{3 \times 17}$

$L = \dfrac{17 \times 10 \times 2}{3 \times 17}$

$L = \dfrac{10 \times 2}{3}$

$L = \dfrac{20}{3}$

Answer: 20/3 ft or 6 2/3 ft

4 0

4 years ago

Melanie invested $3800 in an account paying in interest rate of 2 3/8% compounded quarterly Sebastian invested $3800 in an accou

nekit [7.7K]

Answer:

$317

Step-by-step explanation:

Formula for compound interest is;

A = P(1 + (r/n))^(nt)

For melanie;

P = $3800

r = 2⅜% = 0.02375

n = 12/4 = 3

t = 16 years

Thus;

A = 3800(1 + (0.02375/3))^(3 × 16))

A ≈ $5548

For Sébastien;

P = $3800

r = 2¾% = 0.0275

n = 12

t = 16

Thus;

A = 3800(1 + (0.0275/12))^(12 × 16))

A ≈ 5865

Difference between Sébastien and Melanie's final amount = $5865 - $5548 = $317

6 0

3 years ago

The total height of three trees is 11 m. Tree A is 1 m shorter than

astraxan [27]

11 = C/2-1 + C/2 + C
12 = C/2 + C/2 + C
12 = 4C/2
12 = 2C
C = 12/2
C = 6
Hence, tree A is 2m (3-1), tree B is 3m (6/2) and tree C is 6m

7 0

3 years ago

I made it easier to read

strojnjashka [21]

what do u mean what is this?

6 0

3 years ago

Read 2 more answers