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Vlada [557]
4 years ago
12

A single layer of gold atoms form a surface whose dimensions are 1.0x10^3 angstroms by 1.0x10^3 angstroms. 1 angstrom=10^-10 met

er.
A)what is the area of this surface in square angstroms? [ ]

B) What is the surface area in square centimeters? [ ]
Mathematics
1 answer:
erastovalidia [21]4 years ago
5 0

Answer:

Part A) 1*10^{6}\ angstroms^{2}

Part B) 1*10^{-10}\ cm^{2}

Step-by-step explanation:

Remember that

When multiply numbers in scientific notation, multiply the coefficients and then add the exponents

Part A) what is the area of this surface in square angstroms?

The area is equal to

A=(1*10^{3})( (1*10^{3})=(1)*(10^{3+3})=1*10^{6}\ angstroms^{2}

Part B) What is the surface area in square centimeters

we know that

1 angstrom=10^-10 m

so

1 angstrom=10^-8 cm

Convert angstroms to cm

(1*10^{3})\ angstroms=(1*10^{3})*(10^{-8})=(1*10^{-5})\ cm

The area is equal to

A=(1*10^{-5})(1*10^{-5})=(1)*(10^{-5-5})=1*10^{-10}\ cm^{2}

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By applying the concept of <em>rigid</em> transformation and the equation of translation we conclude that the coordinates of points K' and M' are (-2, 3) and (-4, 1).

<h3>How to apply a translation to a point on a Cartesian plane</h3>

<em>Rigid</em> transformations are transformations applied onto <em>geometric</em> loci such that Euclidean distance is conserved at every point of the loci. Translations are an example of <em>rigid</em> transformations, whose formula is defined by the following expression:

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If we know that K(x, y) = (4, 1), M(x, y) = (2, -1) and \vec v = (-6, 2), then the coordinates of points K' and M' are:

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By applying the concept of <em>rigid</em> transformation and the equation of translation we conclude that the coordinates of points K' and M' are (-2, 3) and (-4, 1).

To learn more on translations: brainly.com/question/17485121

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