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AlekseyPX
3 years ago
8

Which method call converts the value in variable stringVariable to an integer?

Computers and Technology
1 answer:
zlopas [31]3 years ago
3 0

Answer:

The correct answer for the given question is Integer.parseInt( string variable );

Explanation:

Integer.parseInt( string variable ); is the method in a java programming language that convert the string into the integer value. It takes a string variable and converted into the integer.

Following are the program in java which convert the string value into an integer value.

class Main  

{

 public static void main(String []args) // main function

{

   String str1 = "10009";

// variable declaration

   int k = Integer.parseInt(str1);

// convert the string into integer.

   System.out.println("Converted into Int:" + k);

}

}

Output:

Converted into Int:10009

Convert.toInt( stringVariable );

Convert.parseInt( stringVariable,Integer.toInt( stringVariable ); are not any method to convert the string into integer .

Therefore the correct answer is :Integer.parseInt( stringVariable );

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Write a C program that reads two hexadecimal values from the keyboard and then stores the two values into two variables of type
sattari [20]

Solution :

#include  $$

#include $$

#include $$

//Converts $\text{hex string}$ to binary string.

$\text{char}$ * hexadecimal$\text{To}$Binary(char* hexdec)

{

 

long $\text{int i}$ = 0;

char *string = $(\text{char}^ *) \ \text{malloc}$(sizeof(char) * 9);

while (hexdec[i]) {

//Simply assign binary string for each hex char.

switch (hexdec[i]) {

$\text{case '0'}:$

strcat(string, "0000");

break;

$\text{case '1'}:$

strcat(string, "0001");

break;

$\text{case '2'}:$

strcat(string, "0010");

break;

$\text{case '3'}:$

strcat(string, "0011");

break;

$\text{case '4'}:$

strcat(string, "0100");

break;

$\text{case '5'}:$

strcat(string, "0101");

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$\text{case '6'}:$

strcat(string, "0110");

break;

$\text{case '7'}:$

strcat(string, "0111");

break;

$\text{case '8'}:$

strcat(string, "1000");

break;

$\text{case '9'}:$

strcat(string, "1001");

break;

case 'A':

case 'a':

strcat(string, "1010");

break;

case 'B':

case 'b':

strcat(string, "1011");

break;

case 'C':

case 'c':

strcat(string, "1100");

break;

case 'D':

case 'd':

strcat(string, "1101");

break;

case 'E':

case 'e':

strcat(string, "1110");

break;

case 'F':

case 'f':

strcat(string, "1111");

break;

default:

printf("\nInvalid hexadecimal digit %c",

hexdec[i]);

string="-1" ;

}

i++;

}

return string;

}

 

int main()

{ //Take 2 strings

char *str1 =hexadecimalToBinary("FA") ;

char *str2 =hexadecimalToBinary("12") ;

//Input 2 numbers p and n.

int p,n;

scanf("%d",&p);

scanf("%d",&n);

//keep j as length of str2

int j=strlen(str2),i;

//Now replace n digits after p of str1

for(i=0;i<n;i++){

str1[p+i]=str2[j-1-i];

}

//Now, i have used c library strtol

long ans = strtol(str1, NULL, 2);

//print result.

printf("%lx",ans);

return 0;

}

4 0
3 years ago
This is your code. &gt;&gt;&gt; A = ['dog''red'] &gt;&gt;&gt; B = [' cat', 'blue']&gt;&gt;&gt;C = ['fish', 'green'] You can impl
natima [27]

Answer:

The answer to this question is given below in the explanation section.

Explanation:

The given Python code is:

>>> A = ['dog''red']

>>> B = [' cat', 'blue']

>>>C = ['fish', 'green']

We can implement an array of this data by using the dictionary in Python.

Dictionary in python:

A dictionary in python stores (key-value) pairs. For example, we can implement the -given arrays A, B, and C in the dictionary as given below:

d={'dog : red', 'cat : blue', 'fish : green'}

print(d['dog']) # Get an entry from a dictionary; prints "red"

print('cat' in d)    # Check if a dictionary has a given key; prints "True"

d['fish'] = 'black'    # Set an entry in a dictionary

print(d['fish'])      # Prints "black"

# print(d['elephant'])  # KeyError: 'elephant' not a key of d

print(d.get('elephant', 'N/A'))  # Get an element with a default; prints "N/A"

print(d.get('fish', 'N/A'))   # Get an element with a default; prints "black"

del d['dog']        # Remove an element from a dictionary

print(d.get('dog', 'N/A')) # "dog" is no longer a key; prints "N/A"

3 0
2 years ago
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Each Google My Business location has a unique ID that applies changes to the right listing.
Soloha48 [4]

Answer:

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Hence, Option C is the right answer.

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3 years ago
How many times will the loop body execute:
Xelga [282]
I’d also say B, which is 2
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#1 is A and #2 is B, but I don't know about #3 and #4.
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