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3 years ago

Please Help Part C Final Part Thanks

Mathematics

2 answers:

Bas_tet [7]3 years ago

5 0

Answer:

your gay

Step-by-step explanation:

alexandr402 [8]3 years ago

4 0

3 blue + 3 yellow = 6 total marbles.

The probability of picking a blue one first would be 3/6 ( 3 blue out of 6 total marbles).

3/6 reduces to 1/2.

After picking the first marble, there would be 5 marbles left in the bag.

The probability of picking a yellow one would be 3/5 ( 3 yellow and 5 total marbles left).

The probability of picking a blue then a yellow then becomes:

1/2 x 3/5 = 3/10 = 0.30 = 30%

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From his eye, which stands 1.59 meters above the ground, Francisco measures the

viva [34]

The height of the skyscraper to the nearest tenth is 234. 95 meters.

<h3>How to determine the height</h3>

From the information given, we have:

angle of elevation = 32°
length of the base, adjacent side = 376 meters
height of the skyscraper, opposite side = x meters

To determine the height of the elevator, let's use the tangent identity

We have that;

tan θ = opposite/ adjacent

The value of the opposite side is 'x' which is the height of the skyscraper and the value of the adjacent side is 376 meters which is the length of the base of the skyscraper

Now, substitute the values, we have;

tan 32 = x/ 376

cross multiply

x = tan 32 × 376

x = 0. 6249 × 376

x = 234. 95 meters

We know that the 'x' represents the opposite side and thus the height of the skyscraper

Thus, the height of the skyscraper to the nearest tenth is 234. 95 meters.

Learn more about angle of elevation here:

brainly.com/question/19594654

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2 years ago

Nora is twice as old as Raj and half as old as Ethan. In 22 years' time. Ethan will be twice as old as Raj. Find Nora's current

Studentka2010 [4]

Answer:

44 because 22 multiplied by 2 is 44

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2 years ago

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2 years ago

(Algebra II ) What is the equation of y = x^3 with the given transformations? vertical compression by a factor of 1/7, horizonta

NNADVOKAT [17]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\

\begin{array}{rllll}
% left side templates
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\mathbb{R}^{{{ B}}x+{{ C}}}+{{ D}}
\end{array}$ $\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\
\bullet \textit{ vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\
\qquad if\ {{ D}}\textit{ is positive, upwards}
\end{array}$

$\bf ----------------------------\\
f(x)=x^3\textit{compression by }\frac{1}{7}\quad or\quad A=7
\\ \quad \\
f(x)=7x^3\impliedby \textit{8 units to the left, or }C=+8
\\ \quad \\
f(x)=7(x+8)^3\impliedby \textit{now, reflection over x-axis, means}
\\ \quad \\
f(x)=-7(x+8)^3\impliedby \textit{a negative leading term's coefficient}$

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2 years ago

Quadrilateral PQRS is located at P (−4, 1), Q (−2, 3), R (1, 1), and S (−2, −2). Russell and Jamie have both classified PQRS dif

Usimov [2.4K]

Answer:

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Step-by-step explanation:

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3 years ago