Answer:
The ratio is 
Explanation:
From the question we are told that
The first minimum of the single slit pattern falls on the fifth maximum of the double slit pattern.
Generally the condition for constructive interference for as single slit is
Here k is the width of the slit and n is the order of the fringe and for single slit n = 1 (cause we are considering the first maxima)
Generally the condition for constructive interference for as double slit is
Here d is the separation between the slit and m is the order of the fringe and for double slit m = 5 (cause we are considering the first maxima)
=> 
So
=> 
So
If one of two interacting charges is doubled, the force between the charges will double.
Explanation:
The force between two charges is given by Coulomb's law
K=constant= 9 x 10⁹ N m²/C²
q1= charge on first particle
q2= charge on second particle
r= distance between the two charges
Now if the first charge is doubled,
we get 
F'= 2 F
Thus the force gets doubled.
Given:
object = 20kg
terminal speed of object = 80 m/s
According to the problem, drag force is proportional to speed, so Fd = kv ; k is some constant
At terminal velocity Vt: Fg = Fdmg = kVtk = mg / Vt = (20.0)(9.8)/(80.0) = 2.45 kg/s
<span>Fd = kv = 2.45v</span>
Fd = 2.45 (30.0) = 73.5 N
Since the two trains are passing in opposite
directions, so this means that their relative velocities will be the sum of the
two trains that is:
<span>
relative velocity = (13 + 28) = 41m/s</span>
<span>
a. The passengers aboard on train B will see that train A is
moving at 41m/sec due east</span>
<span>b. The passengers aboard on train A will see that
train B is moving at 41m/sec due west</span>
Carbon Dioxide is what you are looking for
