Answer:
a) 16.4 m/s
b) 16.4 m/s
c) 16.4 m/s
Explanation:
a)
m = mass of the snowball = 0.690 kg
h = height of the cliff = 8.25 m
v₀ = initial speed of ball at the time of launch = 10.3 m/s
v = speed of the ball as it reach the ground
Using conservation of energy
initial kinetic energy + initial potential energy at the cliff = final kinetic energy just before reaching the ground
(0.5) m v₀² + mgh = (0.5) m v²
(0.5) v₀² + gh = (0.5) v²
(0.5) (10.3)² + (9.8 x 8.25) = (0.5) v²
v = 16.4 m/s
b)
As the launch angle is changed, the speed of the ball just before reaching the ground remain the same as the final speed does not depend on the angle of launch.
v = 16.4 m/s
c)
As the mass is changed, the speed of the ball just before reaching the ground remain the same as the final speed does not depend on the mass of the ball.
v = 16.4 m/s
There 2 forces acting in oppisite derections on a object
Energy can not be created or destroyed but can change from one form to another.
example: as a roller coaster cart loses height the more speed it gains, the potential energy is transferred into kenetic energy
Answer:
<em>The motorboat ends up 7.41 meters to the west of the initial position
</em>
Explanation:
<u>Accelerated Motion
</u>
The accelerated motion describes a situation where an object changes its velocity over time. If the acceleration is constant, then these formulas apply:
The problem provides the conditions of the motorboat's motion. The initial velocity is 6.5 m/s west. The final velocity is 1.5 m/s west, and the acceleration is 
to the east. Since all the movement takes place in one dimension, we can ignore the vectorial notation and work with the signs of the variables, according to a defined positive direction. We'll follow the rule that all the directional magnitudes are positive to the east and negative to the west. Rewriting the formulas:
Solving the first one for t
We have
Using these values
We now compute x
The motorboat ends up 7.41 meters to the west of the initial position
