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Tom [10]
4 years ago
9

The energy emitted from the sun is a product of ________.

Physics
1 answer:
Tamiku [17]4 years ago
3 0
Q. The energy emitted from the sun is a product of ________.

A. Fusion
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A distracted driver is driving towards a turn where the edge of the road leads into a 75.0 m cliff. The velocity of the vehicle
Vlada [557]

As long as the car is on the road, it moves with a constant speed of 80km/h.

As soon as the car starts to fall down the cliff, it follows a parabolic motion. It means that it still moves with constant speed along the x axis, but it also starts to move along the y axis, with constant acceleration (i.e. the acceleration due to gravity).

The good thing about parabolic motions is that the two motions along the x and y axes are completely separable.

So, first of all, we need to know how long it takes for an object to fall for 75m. The equation of a constantly accelerated motion is

s=s_0+v_0t+\dfrac{1}{2}at^2

Where s_0 is the initial position, v_0 is the initial speed, and a is the constant rate of acceleration. In our case, we start from an initial height of 75m, an initial (vertical!) speed of zero, and our acceleration is -g. So, our equation becomes

s=75-\dfrac{g}{2}t^2

And we want to solve for the time when s=0 (i.e. we want to know how long will it take for the object to reach the ground). We have

0=75-\dfrac{g}{2}t^2 \iff 75=\dfrac{g}{2}t^2 \iff \dfrac{2\cdot75}{g}=t^2 \iff t=\sqrt{\dfrac{150}{g}}

(I'm discarding the negative solution because it wouldn't make sense)

Now that we've used the vertical motion to find out the falling time, we can go back to the horizontal motion. We know that the car moves for a certain amount of time at a certain speed. So, we simply have to plug our values in the s=vt equation, to get

s=80\sqrt\dfrac{150}{g}}

This is how far from the base of the cliff the vehicle lands.

3 0
3 years ago
By how many newtons does the weight of a 85.9-kg person lose when he goes from sea level to an altitude of 6.33 km if we neglect
sergejj [24]

Answer:

Weight\ loss=1.6321N

Explanation:

From the question we are told that:

Weight W=85.9kg

Altitude h= 6.33 km

Let

Radius of Earth r=6380km

Gravity g=9.8m/s^2

Generally the equation for Gravity at altitude is mathematically given by

 g_s=9.8(\frac{6380}{6380+6.33})^2

 g_s=9.781m/s^2

Therefore

Weight at sea level

 W_s=9.8*85.9

 W_s=841.82N

Weight at 6.33 altitude

 W_a=9.781*85.9

 W_a=840.2N

Therefore

 Weight loss=W_s-W_b

 Weight loss=841.82-840.2

 Weight loss=1.6321N

3 0
3 years ago
Tonks changes her hair color for a party with a red color rinse. The next day, she washes the color out of her hair and it retur
Sergeu [11.5K]

Answer: No , a chemical change has not occured as it was easily reversed.

Explanation:

Chemical change is defined as a change in which rearrangement of atoms take place and leads to formation of new substances. It can only be reversed with the help of a chemical reaction.

Physical change is defined as a change which leads to change in shape, size or state of the substance changes. No new substance is formed.It can be easily reversed.

As the hair colour was washed out and returned to its original brown colour, it was a physical change.

5 0
3 years ago
According to Coulomb’s Law, the force between two charged objects is related to _____. the distance separating them the mass of
exis [7]

The force between two charges objects is related to separation.


6 0
3 years ago
Read 2 more answers
What is the charge on an object that has 1.09x10^13 excess electrons?
Nadya [2.5K]

Answer:

-1.74\cdot 10^{-6} C

Explanation:

The electron is the particle that rotates around the nucleus of the atom; it has a negative electric charge equal to :

e=-1.6\cdot 10^{-19}C

which is known as fundamental charge.

For an object containing N excess electrons, the total charge of the object is

Q=Ne

In this problem, the number of excess electrons in the object is:

N=1.09\cdot 10^{13}

Therefore, by plugging it the numbers, we can find the value of Q, the total charge of the object:

Q=(1.09\cdot 10^{13})(-1.6\cdot 10^{-19})=-1.74\cdot 10^{-6} C

5 0
4 years ago
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