Answer:
q = 3.6 10⁵ C
Explanation:
To solve this exercise, let's use one of the consequences of Gauss's law, that all the charge on a body can be considered at its center, therefore we calculate the electric field on the surface of a sphere with the radius of the Earth
r = 6 , 37 106 m
E = k q / r²
q = E r² / k
q = 
q = 4.5 10⁵ C
Now let's calculate the charge on the planet with E = 222 N / c and radius
r = 0.6 r_ Earth
r = 0.6 6.37 10⁶ = 3.822 10⁶ m
E = k q / r²
q = E r² / k
q = 
q = 3.6 10⁵ C
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Answer:
Explanation:
Speed and medium are properties of a wave which is in common within an area of the spectrum of visible light. i.e;
Their medium of propagation
They both travel at the same speed ( speed of light )
The properties mentioned above are properties that define that wave is found within an area spectrum for visible light.
Wish I Could Help You!
Options
a. The worker carried the lunch up to the 53rd floor in the elevator.
b. The worker got a ride in a helicopter to the top of the 68-floor building and then carried the lunch down in the elevator to the 53rd floor?
c. The Worker carried it up the stairs to the 53rd floor.
d. Gravitational potential energy does not depend on the path taken.
Answer:
The gravitational Energy would remain the same in all cases.
Explanation:
Gravitational Energy is a conservative energy and its potential energy comes from gravitational actions.
An instance is when someone lifts a weight from the floor to a certain height and then dropped the weight back to the floor; the work done by the field will not be altered at all; it'll be the same throughout.
If otherwise, it'll be against thermodynamics 2nd law of physics because the object would have remaining energy after returning to the starting point,
For this reason, the gravitational potential energy only depends from the height, and is independent from the path taken to reach there.
Answer:
J = 14.4 kg*m^2
Explanation:
Assuming that the wheel is not moving anywhere, and the kinetic energy is only due to rotation:
Ek = 1/2 * J * w^2
J = 2 * Ek / (w^2)
We need the angular speed in rad / s
566 rev/min * (1 min/ 60 s) * (2π rad / rev) = 58.22 rad/s
Then:
J = 2 * 24400 / (58.22^2) = 14.4 kg*m^2
