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belka [17]
3 years ago
5

Two passenger trains are passing each other on adjacent tracks. train a is moving east with a speed of 13 m/s, and train b is tr

aveling west with a speed of 28 m/s.(a) what is the velocity (magnitude and direction) of train a as seen by the passengers in train b? (b) what is the velocity (magnitude anddirection) of train b as seen by the passengers in train a?
Physics
2 answers:
harkovskaia [24]3 years ago
8 0

Answer:

B and C

Explanation:

alukav5142 [94]3 years ago
7 0

Since the two trains are passing in opposite directions, so this means that their relative velocities will be the sum of the two trains that is: 

<span>
relative velocity = (13 + 28) = 41m/s</span>

<span>
a. The passengers aboard on train B will see that train A is moving at 41m/sec due east</span>

 

<span>b. The passengers aboard on train A will see that train B is moving at 41m/sec due west</span>

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A cricket ball has mass 0.155 kg. If the velocity of a bowled ball has a magnitude of 35.0 m/s and the batted ball's velocity is
FinnZ [79.3K]

Answer:

Magnitude of change in momentum = 4.65 kg.m/s

Magnitude of impulse = 4.65 kg.m/s

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Explanation:

Mass of the cricket ball, m = 0.155 kg

Initial velocity of the ball, u = 35.0 m/s

final velocity of the ball after hitting the bat, v = 65.0 m/s

Time of contact, t = 2.00 ms = 2.00 × 10⁻³ s

Now,

Magnitude of change in momentum = Final momentum - Initial momentum

or

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or

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or

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Now, Magnitude of impulse = change in momentum

thus,

Magnitude of impulse = 4.65 kg.m/s

Now,

magnitude of the average force applied by the bat = \frac{\textup{Impulse}}{\textup{Time}}

or

magnitude of the average force applied by the bat = \frac{\textup{4.65}}{\textup{3}\times\textup{10}^{-3}}

or

Magnitude of the average force applied by the bat = 1550 N

6 0
4 years ago
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Explanation:

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3 years ago
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