Here we must see in how many different ways we can select 2 students from the 3 clubs, such that the students <em>do not belong to the same club. </em>We will see that there are 110 different ways in which 2 students from different clubs can be selected.
So there are 3 clubs:
- Club A, with 10 students.
- Club B, with 4 students.
- Club C, with 5 students.
The possible combinations of 2 students from different clubs are
- Club A with club B
- Club A with club C
- Club B with club C.
The number of combinations for each of these is given by the product between the number of students in the club, so we get:
- Club A with club B: 10*4 = 40
- Club A with club C: 10*5 = 50
- Club B with club C. 4*5 = 20
For a total of 40 + 50 + 20 = 110 different combinations.
This means that there are 110 different ways in which 2 students from different clubs can be selected.
If you want to learn more about combination and selections, you can read:
brainly.com/question/251701
Answer:
2/5
Step-by-step explanation:
She completed 8 out of 20 so we divide 8 by 20
8/20 can be simplified if we divide both the numerator and denominator by 4
which equals 2/5
Answer:
x=1......................
Answer:
0.4
Step-by-step explanation:
Hopefully this can help
The degree is 5, so the largest exponent of the polynomial is 5. This means the answer is either A or B. Choice C is ruled out because the degree here is 7. Choice D is ruled out because the degree here is 6
For choice A, the leading coefficient is 6. This is the number to the left of the variable term of the largest exponent. So we can rule out choice A (because the leading coefficient should be 7)
Choice B is the answer. It has a degree of 5 and a leading coefficient of 7 and also a constant term of 6. The constant term is simply the term without any variables attached to it.
