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andreev551 [17]
3 years ago
7

Simply (6x -2) 2 (0.5) 4

Mathematics
1 answer:
juin [17]3 years ago
5 0
(6x -2) 2 (0.5) 4
(6x -2) 4
24x -8
Solution
24x -8
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Consider the following equation: f(x)=x^2+4\4x^2-4x-8 name the vertical asymptote(s)
zhenek [66]

ANSWER

The vertical asymptotes are


\Rightarrow x=2\:or\:x=-1

<u>EXPLANATION</u>

We have

f(x)=\frac{x^2+4}{4x^2-4x-8}


For vertical asymptotes we set the denominator to zero and solve the quadratic equation;

4x^2-4x-8=0


\Rightarrow x^2-x-2=0

We split the middle term to obtain,

x^2+x-2x-2=0

\Rightarrow x(x+1)-2(x+1)=0


\Rightarrow (x-2)(x+1)=0


\Rightarrow x=2\:or\:x=-1


Therefore the vertical asymptotes are


x=2\:or\:x=-1





3 0
3 years ago
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In most microcomputers the addresses of memory locations are specified in hexadecimal. These addresses are sequential numbers th
iren [92.7K]

Considering that the addresses of memory locations are specified in hexadecimal.

a) The number of memory locations in a memory address range ( 0000₁₆ to FFFF₁₆ )  = 65536 memory locations

b) The range of hex addresses in a microcomputer with 4096 memory locations is ;  4095

<u>applying the given data </u>:

a) first step : convert FFFF₁₆ to decimal           ( note F₁₆ = 15 decimal )

( F * 16^3 ) + ( F * 16^2 ) + ( F * 16^1 ) + ( F * 16^0 )

= ( 15 * 16^3 ) + ( 15 * 16^2 ) + ( 15 * 16^1 ) + ( 15 * 1 )

=  61440 + 3840 + 240 + 15 = 65535

∴ the memory locations from  0000₁₆ to FFFF₁₆ = from 0 to 65535 = 65536 locations

b) The range of hex addresses with a memory location of 4096

= 0000₁₆ to FFFF₁₆ =  0 to 4096

∴ the range = 4095

Hence we can conclude that the memory locations in ( a ) = 65536 while the range of hex addresses with a memory location of 4096 = 4095.

Learn more : brainly.com/question/18993173

6 0
2 years ago
Which equation represents a line that passes through (4, left-parenthesis 4, StartFraction one-third EndFraction right-parenthes
Alina [70]

Answer:

y-\frac{1}{3}=\frac{3}{4}(x-4)

Step-by-step explanation:

we know that

The equation of the line into point slope form is equal to

y-y1=m(x-x1)

In this problem we have

point\ (4,\frac{1}{3})

m=\frac{3}{4}

substitute the given values

y-\frac{1}{3}=\frac{3}{4}(x-4)

y minus StartFraction one-third EndFraction equals StartFraction 3 Over 4 EndFraction left-parenthesis x minus 4 right-parenthesis.(x – 4)

7 0
3 years ago
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Round 6.443 to the nearest hundredth.
Gnesinka [82]
6.44 hope this helps
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3 years ago
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Help please!!! Which graph represents a system of equations with NO SOLUTION. Explain how you know.​
ELEN [110]

Answer:graph B

Step-by-step explanation:because if a line is parallel they have no solutions with a certain slope

If two lines intersect then they must have at least a solution

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2 years ago
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