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lisabon 2012 [21]
3 years ago
12

What is the x intercept that is perpendicular to y=4/3x+1 and passes through (-4,9)

Mathematics
1 answer:
kolezko [41]3 years ago
5 0
Well, we know the line is perpendicular to that one above.... what is the slope of that one anyway?  well, notice, the equation is already in slope-intercept form   \bf y=\stackrel{slope}{\cfrac{4}{3}}x+1.

so, we're looking for the equation of a line perpendicular to that one, now, since that one has a slope of 4/3, a perpendicular line will have a negative reciprocal slope to that one, 

\bf \textit{perpendicular, negative-reciprocal slope for}\quad \cfrac{4}{3}\\\\
negative\implies  -\cfrac{4}{ 3}\qquad reciprocal\implies - \cfrac{ 3}{4}

so, what is the equation of a line whose slope is -3/4 and runs through -4,9?

\bf \begin{array}{ccccccccc}
&&x_1&&y_1\\
&&(~ -4 &,& 9~)
\end{array}
\\\\\\
% slope  = m
slope =  m\implies -\cfrac{3}{4}
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-9=-\cfrac{3}{4}[x-(-4)]
\\\\\\
y-9=-\cfrac{3}{4}(x+4)

now, the x-intercept for any function is found by zeroing out the "y" and solving for "x", thus

\bf y-9=-\cfrac{3}{4}(x+4)\implies 0-9=-\cfrac{3}{4}(x+4)\implies -9=-\cfrac{3x}{4}-3
\\\\\\
-6=-\cfrac{3x}{4}\implies -24=-3x\implies \cfrac{-24}{-3}=x\implies 8=x

x = 8, y = 0           ( 8 , 0 )
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