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Orlov [11]
3 years ago
6

Y=x-3 determine the slope

Mathematics
1 answer:
Anettt [7]3 years ago
7 0
It is the answer M: 1
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Solve the equation<br> -7=y/7
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Add (4x^2-xy-y^2) and (x^2+5xy+8y^2) simplify your answer:
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for f(x)=(x-3)/(x^(2)-4), the function is at x=2 continuous discontinuous with an infinite discontinuity discontinuous with a ju
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2 years ago
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A circle is centered at the point (-3, 2) and passes through the point (1, 5). The radius of the circle is ______ units. The poi
nalin [4]
Circle formula
(x-h)^2+(y-k)^2=r^2 where (h,k) is the center
and r=radius

to find the radius
we are given one of the points and the center
distnace from them is the radius
distance formula
D=\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}
points (-3,2) and (1,5)
D=\sqrt{(1-(-3))^{2}+(5-2)^{2}}
D=\sqrt{(4)^{2}+(3)^{2}}
D=\sqrt{16+9}
D=\sqrt{25}
D=5

center is -3,2
r=5
input
(x-(-3))^2+(y-2)^2=5^2
(x+3)^2+(y-2)^2=25 is equation
radius =5
input -7 for x and solve for y
(-7+3)^2+(y-2)^2=25
(-4)^2+(y-2)^2=25
16+(y-2)^2=25
minus 16
(y-2)^2=9
sqqrt
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add 2
y=2+/-3
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the point (-7,5) and (7,-1) lie on this circle



radius=5 units
the points (-7,5) and (-7,1) lie on this circle

3 0
3 years ago
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