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3 years ago

The perimeter of is _____.

Mathematics

2 answers:

zimovet [89]3 years ago

7 0

B is the best answer

bagirrra123 [75]3 years ago

5 0

B IS THE ANSEWER TO THE PROBLEM

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PLEASE HELP IT"S DUE IN 20 MINS!!!

BlackZzzverrR [31]

Answer:

the available molding is not enough the molding is 1 inch shorter

Step-by-step explanation:

convert 13 feet into inches then add the 9 inches

7 0

2 years ago

-4x-10x simplify the expression

n200080 [17]

Answer:

= -14x

Step-by-step explanation:

Since the equation is saying to subtract 10x, we are going to change the minus sign to a addition sign and change positive 10 to negative and continue the rest.

4 0

3 years ago

Read 2 more answers

A colony of bacteria is growing at a rate of 0.2 times its mass. Here time is measured in hours and mass in grams. The mass of t

11Alexandr11 [23.1K]

Answer:

Question 1: $dm/dt=0.2m$

Question 2: $m=Ae^{(0.2t)}$

Question 3: $m=10e^{(0.2t)}$

Question 4: $m=10g$

Explanation:

Question 1: Write down the differential equation the mass of the bacteria, m, satisfies: m′= .2m

a) By definition: $m'=dm/dt$

b) Given: $rate=0.2m$

c) By substitution: $dm/dt=0.2m$

Question 2: Find the general solution of this equation. Use A as a constant of integration.

a) Separate variables

$dm/m=0.2dt$

b) Integrate

$\int dm/m=\int 0.2dt$

$ln(m)=0.2t+C$

c) Antilogarithm

$m=e^{0.2t+C}$

$m=e^{0.2t}\cdot e^C$

$e^C=A\\\\m=Ae^{(0.2t)}$

Question 3. Which particular solution matches the additional information?

Use the measured rate of 4 grams per hour after 3 hours

$t=3hours,dm/dt=4g/h$

First, find the mass at t = 3 hours

$dm/dt=0.2m\\\\4=0.2m\\\\m=4/0.2\\\\m=20g$

Now substitute in the general solution of the differential equation, to find A:

$m=Ae^{(0.2t)}\\\\20=Ae^{(0.2\times 3)}\\\\A=20/e^{(0.6)}\\\\A=10.976$

Round A to 1 significant figure:

A = 10.

Particular solution:

$m=10e^{(0.2t)}$

Question 4. What was the mass of the bacteria at time =0?

Substitute t = 0 in the equation of the particular solution:

$m=10e^{0}\\\\m=10g$

3 0

3 years ago

Julio's father is 4 times as old as Julio. The sum of their ages is no less than 55.

seropon [69]

Call (F) the age of the father and (J) the age of Julio

The F & J are related in this way: F=4J

Now you have a restriction in the form of inequality: The sum of both ages has to be greater or equal than 55.

Algebraically that is: F + J ≥ 55

You can substitute F with 4J to find the solution for J:

4J + J ≥ 55

5J ≥ 55

Now divide both sides by 5

5J/5 ≥ 55/5

J ≥ 11

That Imposes a lower boundary for the value of J of 11, meaning that the youngest age of Julio can be 11

8 0

3 years ago

How to write 4.651 in expanded form with decimals?

dsp73

Answer:

$0.4651 \times {10}^{1}$

5 0

2 years ago