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wlad13 [49]
3 years ago
14

Can someone pls help me with this? I will give 20 points

Mathematics
1 answer:
Ierofanga [76]3 years ago
4 0
Okay here we go!

The answer is D. 

Because when you solve the equation you get 2 and that means the arrow has to be or end at 2.


HOPE THIS HELPED! :)
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What’s the work and answer for this? Someone please tell me
Arturiano [62]

Answer:  14

Step-by-step explanation:

We arrange the number as -3,  1, 7, 8, 18, 19, 42, the old median is 8.

But the median has change to 11 when the number is add, which means that the number is between 7 and 18.

(8 + x)/2 = 11      Where x is the new number

8 + x = 22

x = 14

4 0
2 years ago
Need help with this as soon as possible, answer quick
Nostrana [21]

Answer:

Given points are,

A'(2,3) and A(3,-4), under the translation.

we get the graph as,

where B is A(3,-4) and A is A'(2,3).

A translation by 1 unit left and 7 units up.

Answer is:

A translation by 1 unit left and 7 units up.

4 0
9 months ago
If you multiply me by 2, I become a number greater than 20 and less than 40 who am I
Alika [10]
Well there are many numbers, starting from 11 though 19.
11 times 2 = 22    12 times 2 = 24   13 times 2 = 26    14 times 2 = 28    15 times 2 = 30      16 times 2 = 32     17 times 2 = 34    18 times 2 = 36     19 times 2 = 38
so basically from any number from 11 through 19.
Hope i helped! :D

8 0
2 years ago
What is 10/12 times 3/5 times 1/4 equal
natima [27]
1/8 is the answer jahdbdjdndndndn
3 0
2 years ago
Read 2 more answers
Determine the type and number of solutions of −4x2 − 3x + 7 = 0.
Kaylis [27]

Answer:

Step-by-step explanation:

You have to use the discriminant for this. If the quadratic is -4x^2-3x+7, then

a = -4, b = -3, and c = 7. The formula for finding the discriminant is

D=b^2-4ac which comes from the quadratic formula, but without the square root sign. Filling in:

D=(-3)^2-4(-4)(7) which simplifies down to

D = 9 + 112 so

D = 121. This is a perfect square, so the solutions will be 2 real. Just so you know, you will NEVER have a solution like the one offered in the third choice down. If you have one imaginary root, you will ALWAYS have a second by the conjugate rule.

7 0
2 years ago
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