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Lesechka [4]
2 years ago
5

Please help! I’ll mark as brainliest

Mathematics
1 answer:
Talja [164]2 years ago
7 0

Answer:

see below

Step-by-step explanation:

domain is all x values for which a graph has
and range is all y values for which a graph has

domain in this case is -4<x<4. The range is -3<= x <= 3

Function is increasing when slope of the line is positive, function is decreasing when slope of the line is negative.

When 2 lines meet and there is an edge like at (-1,3) there is no increase of decrease of the function. If you are in calculus, this is because the derivative of the function will not be valid at those points. If you are not in calculus, then don't pay attention to the derivative stuff.

Function is increasing on interval -4<x<-1 and 2<x<4
Function is decreasing on interval -1<x<2

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Solve for x: 4 over x plus 4 over quantity x squared minus 9 equals 3 over quantity x minus 3. (2 points) Select one: a. x = -4
Kay [80]

Answer:

<h2>c. x = -4 or x = 9</h2>

Step-by-step explanation:

\dfrac{4}{x}+\dfrac{4}{x^2-9}=\dfrac{3}{x-3}

Domain:

x\neq0\ \wedge\ x^2-9\neq0\ \wedge\ x-3\neq0\\\\x\neq0\ \wedge\ x\neq\pm3

solution:

\dfrac{4}{x}+\dfrac{4}{x^2-3^2}=\dfrac{3}{x-3}

use <em>(a - b)(a + b) = a² - b²</em>

\dfrac{4}{x}+\dfrac{4}{(x-3)(x+3)}=\dfrac{3}{x-3}

multiply both sides by (x - 3) ≠ 0

\dfrac{4(x-3)}{x}+\dfrac{4(x-3)}{(x-3)(x+3)}=\dfrac{3(x-3)}{x-3}

cancel (x - 3)

\dfrac{4(x-3)}{x}+\dfrac{4}{x+3}=3

subtract \frac{4(x-3)}{x} from both sides

\dfrac{4}{x+3}=3-\dfrac{4(x-3)}{x}\\\\\dfrac{4}{x+3}=\dfrac{3x}{x}-\dfrac{(4)(x)+(4)(-3)}{x}\\\\\dfrac{4}{x+3}=\dfrac{3x-\bigg(4x-12\bigg)}{x}\\\\\dfrac{4}{x+3}=\dfrac{3x-4x-(-12)}{x}\\\\\dfrac{4}{x+3}=\dfrac{-x+12}{x}

cross multiply

(4)(x)=(x+3)(-x+12)

use FOIL

4x=(x)(-x)+(x)(12)+(3)(-x)+(3)(12)\\\\4x=-x^2+12x-3x+36

subtract 4x from both sides

0=-x^2+12x-3x+36-4x

combine like terms

0=-x^2+(12x-3x-4x)+36\\\\0=-x^2+5x+36

change the signs

x^2-5x-36=0\\\\x^2-9x+4x-36=0\\\\x(x-9)+4(x-9)=0\\\\(x-9)(x+4)=0

The product is 0 if one of the factors is 0. Therefore:

x-9=0\ \vee\ x+4=0

x-9=0            <em>add 9 to both sides</em>

x=9\in D

x+4=0          <em>subtract 4 from both sides</em>

x=-4\in D

7 0
3 years ago
Nine less than one forth of a number is 6
snow_lady [41]

Answer:

x = 60

Step-by-step explanation:

<u>Step 1:  Convert into an equation</u>

Nine less than one forth of a number is 6

1/4x - 9 = 6

<u>Step 2:  Add 9 to both sides</u>

1/4x - 9 = 6

1/4x - 9 + 9= 6+ 9

1/4x = 15

<u>Step 3:  Multiply both sides by 4</u>

1/4x * 4 = 15 * 4

x = 60

Answer:  x = 60

6 0
2 years ago
Steph made the box-and-whisker plot shown.
sdas [7]

Answer:

B.60

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Simplify (5x^2 -3x+3) - (x^2+2x-1).
Natali [406]
Eliminate parenthesis by using the distribution property

= 5x² -3x +3 - x² - 2x +1

Group similar terms

= (5-1)*x² + (-3 -2)*x + (3+1)

Then sum everything:

= 4x² -5x +4





7 0
3 years ago
Read 2 more answers
If mr. douty goes to the store and purchases 5 equally priced items for a total of $172.45, how much did each item cost individu
natima [27]

Answer:

$34.49

Step-by-step explanation:

To figure out this problem, you would need to divide the total price by the total amount of items you are buying

In this case it is...

172.45/5

=34.49

So the price of each item is approx. $34.49

5 0
2 years ago
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