Question

The diagram shows a right triangle and three squares. The area of the largest square is 67 units squared.

Answer 1

Answer:

c 11 and 56 A 8 and 58

Step-by-step explanation:

Answer 2

Answer:

B. 7 and 60

C. 11 and 56

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The area of the three squares must satisfy the Pythagorean Theorem

so

$c^2=a^2+b^2$

where

c^2 is the area of the largest square

a^2 and b^2 are the areas of the smaller squares

$67=a^2+b^2$

The sum of the areas of the smaller squares must be equal to 67

therefore

7 and 60 ----> could be the areas of the smaller squares (60+7=67)

11 and 56 ----> could be the areas of the smaller squares (11+56=67)