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2 years ago

Eight members of a school marching band are auditioning for 3 drum major

Mathematics

1 answer:

Doss [256]2 years ago

7 0

Answer:

Step-by-step explanation:

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40% of lightbulb produced by shining beauty company have suboptimal performance. 5 bulbs are chosen for test. find the probabili

omeli [17]

(a) about 68.3%

(b) about 83.1%

(c) about 67.7%

4 0

3 years ago

Help asappppp? i’m having trouble on wat the 1/4 point is

blagie [28]

Answer:

(-14, 5.5)

Step-by-step explanation:

Perhaps the easiest way to find the 1/4 point is to find (x, y), then find the midpoint between that and M.

(x, y) = 2M -(13, 25) = 2(-5, 12) -(13, 25) = (-23, -1)

Then the 1/4 point is ...

((-23, -1) +M)/2 = ((-23, -1) +(-5, 12))/2 = (-28, 11)/2 = (-14, 5.5)

_____

If we call the end points A(x, y) and B(13, 25), then we know ...

M = (A+B)/2

A = 2M -B . . . . we'll need this in a bit

and the 1/4 point Q is such that ...

(Q -A)/(B -A) = 1/4

4Q -4A = B -A . . . . cross multipliy

Q = (B +3A)/4 = (B +3(2M -B))/4 = (6M -2B)/4 . . . . solve for Q

Q = (3M -B)/2 . . . . reduce the fractions

Q = (3(-5, 12) -(13, 25))/2 = (-28, 11)/2 = (-14, 5.5) . . . as above

6 0

2 years ago

Two numbers given in certain radix x are (55)x and (64)x . If we add this two numbers, the result is (130)x. What is the radix x

wlad13 [49]

the answer is x = 9.

4 0

3 years ago

A certain change in a process for manufacture of component parts is being considered. Samples are taken using both the existing

Katyanochek1 [597]

Answer:

a) The confidence interval is $0.00\leq\pi_1-\pi_2\leq0.02$ .

Step-by-step explanation:

We have to calculate a confidence interval (CI) of a difference of proportions.

For the existing procedure, the proportion is:

$p_1=75/1500=0.05$

For the new procedure, the proportion is:

$p_2=80/2000=0.04$

To calculate the CI, we need to estimate the standard deviation

$s=\sqrt{\frac{p_1(1-p_1)}{n_1} +\frac{p_2(1-p_2)}{n_2} }\\\\s=\sqrt{\frac{0.05(1-0.05)}{1500} +\frac{0.04(1-0.04)}{2000} }=\sqrt{ 0.000032 + 0.000019 }=\sqrt{ 0.000051 }\\\\s=0.007$

For a 90% CI, the z-value is 1.64.

Then, the CI is:

$(p_1-p_2)-z*\sigma \leq\pi_1-\pi_2\leq(p_1-p_2)+z*\sigma \\\\(0.05-0.04)-1.64*0.007\leq\pi_1-\pi_2\leq(0.05-0.04)+1.64*0.007\\\\0.01-0.01\leq\pi_1-\pi_2\leq0.01+0.01\\\\0.00\leq\pi_1-\pi_2\leq0.02$

6 0

3 years ago

A video posted on the internet is becoming very popular, and the total number of views is increasing by 20% every hour. If the v

Ierofanga [76]

Answer:198000 maybe

Sorry if it’s wrong

3 0

2 years ago