Eight members of a school marching band are auditioning for 3 drum major

Solve 91 - 2 + 7k| +1 = 46

mylen [45]

Answer:

k = -6.29

Step-by-step explanation:

91 - 2 + 7k + 1 = 46

add all like terms

90 + 7k =46

subtract

90 + 7k = 46

-90 -90

------------------------

7k = -44

divide

$\frac{7k}{7}$ = $\frac{-44}{7}$ (these arent fractions thats just how i divide things :))

= -6.28571428571

round to nearest hundredth

k= -6.29

goes up to 9 because 5 makes 8 go up one when rounding

sorry for asking so many questions. hope this helps

7 0

2 years ago

1. Which words represent ADDITION less than sum more than times

Vlad1618 [11]

Answer:

more than

Step-by-step explanation:

8 0

2 years ago

Suppose a normal distribution has a mean of 266 and a standard deviation of

Elis [28]

Answer:

I think the answer is P(x>178)

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

let X represent the amount of time till the next student will arriv ein the library partking lot at the university. If we know t

AlekseyPX

Answer:

0.606531 = 60.6531% probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot.

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

Mean of 4 minutes

This means that $m = 4, \mu = \frac{1}{4} = 0.25$

Find the probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot:

This is:

$P(2 \leq X \leq 132) = P(X \leq 132) - P(X \leq 2)$

In which

$P(X \leq 132) = 1 - e^{-0.25*132} = 1$

$P(X \leq 2) = 1 - e^{-0.25*2} = 0.393469$

$P(2 \leq X \leq 132) = P(X \leq 132) - P(X \leq 2) = 1 - 0.393469 = 0.606531$

0.606531 = 60.6531% probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot.

4 0

2 years ago

A dairy company gets milk from two dairies and then blends the milk to get the desired amount of butterfat. Milk from dairy I co

lisov135 [29]

Answer:

The complete solution and step by step explanation is written below.

Note:

Here is the complete question you were probability asking as you may have unintentionally missed to mention the parts (a) and (b). So, after a little research, I figured out that this was probably the complete question you had meant to ask. So, I am answering based on the reference of this complete question that may indeed clear your concepts.

Complete Question:

A dairy company gets milk from two dairies and then blends the milk to get the desired amount of butterfat. Milk from dairy I costs $2.40 per gallon, and milk from dairy II costs $0.80 per gallon. At most $144 is available for purchasing milk. Dairy I can supply at most 50 gallons averaging 3.9% butterfat, and dairy II can supply at most 80 gallons averaging 2.9% butterfat. Answer parts a and b.

A. How much milk from each supplier should the company buy to get at most 100 gallons of milk with the maximum amount of butterfat? (Also, what IS the maximum amount of butterfat?)

B. The solution from part A leaves both dairy 1 and dairy 2 with excess capacity. Calculate the amount of additional milk each dairy could produce.

Step-by-step explanation:

Let A be number of gallons of the amount of milk the company bought from Dairy 1.

(100 - X) be the number of gallons of the amount of milk the company bought from Dairy 2.

Milk from dairy I costs $2.40 per gallon and milk from dairy II costs $0.80 per gallon.

So, the equation of total cost available for purchasing the milk be:

Cost = 2.40A + ( 100 - A)0.80

As $144 is the total cost available for purchasing the milk.

Hence, Cost equation would be as follows:

Cost = 2.40A + ( 100 - A)0.80

144 = 2.40A + ( 100 - A)0.80

144 = 2.40A + 80 - 0.80A

1.6A = 64

So, A = 64 ÷ 1.6

= 40 gallons

Calculation of gallons of Dairy 1 and Dairy 2:

gallons of Dairy 1 ⇒ A = 40 gallons

gallons of Dairy 1 ⇒ 100 - A = 100 - 40 = 60 gallons

The equation for Fat will be:

Fat for dairy 1 = 40 × 3.9% = 1.56

Fat for dairy 2 = 60 × 2.9% = 1.74

ADD = 1.56 + 1.74 = 3.3 %

Calculation Part B:

Dairy 1 will have = 50 - 40 = 10 gallons ( excess)

Dairy 2 will have = 80 - 60 = 20 gallons (excess)

Keywords: word problem, equation solving

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5 0

2 years ago