<h2>
Answer:</h2>

<h2>
Step-by-step explanation:</h2>
As the question states,
John's brother has Galactosemia which states that his parents were both the carriers.
Therefore, the chances for the John to have the disease is = 2/3
Now,
Martha's great-grandmother also had the disease that means her children definitely carried the disease means probability of 1.
Now, one of those children married with a person.
So,
Probability for the child to have disease will be = 1/2
Now, again the child's child (Martha) probability for having the disease is = 1/2.
Therefore,
<u>The total probability for Martha's first child to be diagnosed with Galactosemia will be,</u>

(Here, we assumed that the child has the disease therefore, the probability was taken to be = 1/4.)
<em><u>Hence, the probability for the first child to have Galactosemia is
</u></em>
Answer:
stratified sample
Step-by-step explanation:
Answer: a) Yes
b) No
Explanation: Substitute the values of X and Y from the given points into the equation. I’ll use a) as an example:
Given point: (1,-3)
Equation: 4x-2y=10
Value of X: 1
Value of Y: -3
Substitute X and Y: 4(1)-2(-3)=10
4-(-6)=10
4+6=10 ✔︎
Therefore, the given ordered pair is a proper solution to the equation 4x-2y=10.
*You can use the same method for question b).*
The rule would be addition. (+300)
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