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Stolb23 [73]
2 years ago
10

The square root to the nearest tenth for 1.19​

Mathematics
2 answers:
miss Akunina [59]2 years ago
7 0

Answer:

√1.19 = 1.09087121146357

8_murik_8 [283]2 years ago
5 0
It’s 1.09 but rounded to the nearest tenth is 1.1
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The point (-7,4) in on the terminal side of an angle t. Find sec (t) to two decimal places.
Sliva [168]

Answer:

  -1.15

Step-by-step explanation:

The tangent of the angle can be found as ...

  tan(t) = (y-coordinate)/(x-coordinate) = -4/7

The secant of the angle is related by ...

  sec(t)² = tan(t)² +1 = (-4/7)² +1 = 65/49

Then the secant of this 2nd-quadrant angle is ...

  sec(t) = -√(65/49) = -(√65)/7 ≈ -1.15

6 0
2 years ago
Find the slope of the line passing through the points (-5,2)<br> and<br> (-8,8).
sattari [20]

Answer:

slope = -2

Step-by-step explanation:

(-5,2) (-8,8)

equation to find slope: \frac{y1 - y2}{x1 - x2}

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7 0
3 years ago
Question 16
anastassius [24]

Step-by-step explanation:

Distance between 2 towns 360 miles showed length 3 inches

1800 miles = ? inches

360 miles = 3 inches

1 miles = 3/360 inches

1800 miles = 3/360 × 1800

= 15 inches

3 0
2 years ago
True or false: the equation tan^2x+1=sec^2x
zhenek [66]

ANSWER

True

EXPLANATION

The given trigonometric equation is:

{ \tan}^{2} x + 1 = { \sec}^{2} x

We take the LHS and simplify to arrive at the RHS.

{ \tan}^{2} x + 1 =  \frac{{ \sin}^{2} x}{{ \cos}^{2} x}  + 1

Collect LCM on the right hand side to get;

{ \tan}^{2} x + 1 =  \frac{{ \sin}^{2} x + {\cos}^{2} x}{{ \cos}^{2} x}

This implies that

{ \tan}^{2} x + 1 =  \frac{1}{{ \cos}^{2} x} .

{ \tan}^{2} x + 1 =  {( \frac{1}{ \cos(x) }) }^{2}

{ \tan}^{2} x + 1 =  { \sec}^{2} x

This identity has been verified .Therefore the correct answer is true.

3 0
2 years ago
Can someone plsss help :)
OLga [1]
Set equal to eachother
(2x+1) = 79
Subtract 1 from both sides
2x=78
Divide 2 from both sides
2x/2=78/2
X= 39
5 0
3 years ago
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