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Lina20 [59]
3 years ago
15

637 x 3 find the products. Show your thinking. The first row gives some ideas for showing your thinking

Mathematics
1 answer:
Colt1911 [192]3 years ago
6 0

Answer:

1,911

Step-by-step example

3 x 7

3 x 30

3 x 600

then add it all up to get the 1,911

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3 mangoes and 2 oranges have a mass of 200gm and 4 mangoes and 4 oranges have a mass of 300gm. Find out the mass of each fruit.
mestny [16]
Start by defining your variables
let x be the mass of a single mango in gm
let y be the mass of a single orange in gm

now, write the question as a system of equations

3 mango and 2 orange have a mass of 200 gm
3x +2y = 200
4 mango and 4 orange have a mass of 300 gm
4x +4y = 300

now you have a system of equations
3x+2y =200
4x+4y =300

solve for x and y
5 0
3 years ago
Read 2 more answers
Sam built a circular fenced-in section for some of his animals .the section has a circumference of 55 meters .what is the approx
otez555 [7]

Answer:

  • 243 m²

Step-by-step explanation:

<u>Area of circle:</u>

  • A = πr²

<u>Circumference of circle:</u>

  • C = 2πr

<u>Given</u>

  • C = 55 m

<u>Find r using the second formula:</u>

  • 2πr = 55
  • 2*3.14r = 55
  • r = 55/6.28
  • r = 8.8 (rounded)

<u>Find area using the first formula:</u>

  • A = 3.14*8.8²
  • A = 243 m² (rounded)

7 0
3 years ago
Solve for ,×. Then, circle whether each angle pair is complementary or supplementary.​
Svet_ta [14]

See the solution above..☝☝

HOPE THIS WILL HELP!!!

<h3>PLZZ PLZZ MARK ME BRAINLIEST!!</h3>

6 0
3 years ago
The answer I got is not one of the options, and I am very confused, because now I don't know what to do?
Effectus [21]
<span>A’(2, -4); B’(7, -9); C’(-2, -9)
I believe you did it correctly but over the wrong line. You were supposed to do it over line M and it looks like you did it over the X-axis.</span>
4 0
3 years ago
Which equation has the solutions x=1+or-square root of 5?
stiv31 [10]

We will proceed to solve each case to determine the solution of the problem.

<u>case a)</u> x^{2}+2x+4=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2}+2x=-4

Complete the square. Remember to balance the equation by adding the same constants to each side.

x^{2}+2x+1=-4+1

x^{2}+2x+1=-3

Rewrite as perfect squares

(x+1)^{2}=-3

(x+1)=(+/-)\sqrt{-3}\\(x+1)=(+/-)\sqrt{3}i\\x=-1(+/-)\sqrt{3}i

therefore

case a) is not the solution of the problem

<u>case b)</u> x^{2}-2x+4=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2}-2x=-4

Complete the square. Remember to balance the equation by adding the same constants to each side.

x^{2}-2x+1=-4+1

x^{2}-2x+1=-3

Rewrite as perfect squares

(x-1)^{2}=-3

(x-1)=(+/-)\sqrt{-3}\\(x-1)=(+/-)\sqrt{3}i\\x=1(+/-)\sqrt{3}i

therefore

case b) is not the solution of the problem

<u>case c)</u> x^{2}+2x-4=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2}+2x=4

Complete the square. Remember to balance the equation by adding the same constants to each side.

x^{2}+2x+1=4+1

x^{2}+2x+1=5

Rewrite as perfect squares

(x+1)^{2}=5

(x+1)=(+/-)\sqrt{5}\\x=-1(+/-)\sqrt{5}

therefore

case c) is not the solution of the problem

<u>case d)</u> x^{2}-2x-4=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

x^{2}-2x=4

Complete the square. Remember to balance the equation by adding the same constants to each side.

x^{2}-2x+1=4+1

x^{2}-2x+1=5

Rewrite as perfect squares

(x-1)^{2}=5

(x-1)=(+/-)\sqrt{5}\\x=1(+/-)\sqrt{5}

therefore

case d) is the solution of the problem

therefore

<u>the answer is</u>

x^{2}-2x-4=0

5 0
2 years ago
Read 2 more answers
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