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astraxan [27]
3 years ago
12

On a coordinate plane, a dashed straight line with negative slope goes through (0, 1) and (2, negative 2). Everything to the lef

t of the line is shaded. Which inequality is represented by the graph? y > Negative two-thirdsx + 1 y < Negative two-thirdsx + 1 y < Negative three-halvesx + 1 y > Negative three-halvesx + 1

Mathematics
2 answers:
charle [14.2K]3 years ago
8 0

Answer:

y

Step-by-step explanation:

The straight line passes through (0,1) and (2,-2).

Equation of a straight line passing through two points (x1,y1) and (x2,y2)

is given by:

y-y_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}(x-x_{1})

y-1=\frac{-2-1}{2-0}(x-0)

y=-\frac{3}{2}x+1

Everything to the left of the line is shaded.

We have to visualize the graph:the straight line has a positive y-intercept and a negative slope.The graph is given in the attachment below.

From the figure we can see origin lies on the shaded region.Hence (0,0) should satisfy the inequality.

LHS=y=0

RHS=-\frac{3x}{2}+1=1\ (x=0)

LHS<RHS as 0<1

Hence , the inequality is:

y

Nastasia [14]3 years ago
3 0

its C on ed

Step-by-step explanation:

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Answer : \frac{49}{4}

Given expression is x^2 - 7x + c

To make perfect square trinominal we use completing the square method

In completing the square method we add and subtract the half of square of coefficient of middle term

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Half of -7 is \frac{-7}{2}

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So the expression becomes x^2 - 7x +  [tex] \frac{49}{4} that gives perfect square trinomial

Hence , the value of 'c' is \frac{49}{4}


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