Question

On a coordinate plane, a dashed straight line with negative slope goes through (0, 1) and (2, negative 2). Everything to the left of the line is shaded. Which inequality is represented by the graph? y > Negative two-thirdsx + 1 y < Negative two-thirdsx + 1 y < Negative three-halvesx + 1 y > Negative three-halvesx + 1

Answer 1

Answer:

$y$

Step-by-step explanation:

The straight line passes through (0,1) and (2,-2).

Equation of a straight line passing through two points (x1,y1) and (x2,y2)

is given by:

$y-y_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}(x-x_{1})$

$y-1=\frac{-2-1}{2-0}(x-0)$

$y=-\frac{3}{2}x+1$

Everything to the left of the line is shaded.

We have to visualize the graph:the straight line has a positive y-intercept and a negative slope.The graph is given in the attachment below.

From the figure we can see origin lies on the shaded region.Hence (0,0) should satisfy the inequality.

LHS=y=0

RHS=$-\frac{3x}{2}+1=1\ (x=0)$

LHS<RHS as 0<1

Hence , the inequality is:

$y$

Answer 2

its C on ed

Step-by-step explanation: